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Zina [86]
2 years ago
9

A liter of milk has a [H] of about 2.51 x 10-7. (You may prefer to think of the hydronium ion concentration, [H3O+], as 2.51 x 1

0-7.) Use the formula for the calculation of pH provided and show each step as you calculate the pH of milk. In order to get full points you must show all the steps you take
Please help!!.​
Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
7 0

Answer:

12-6

Explanation:

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1. Generally speaking, where on the periodic table are the elements that form ions requiring!
Artemon [7]

Answer:

The middle, or the transitional metals

Explanation:

When naming elements, we use roman numerals to indicate what their charge is. The charge of an element is affected by their number of valence electrons (outermost electrons).

Transitional metals are generally <u>multivalent</u>, meaning that element has more than one possible number of valence electrons. This makes them have more than one possible charge. Roman numerals indicate which charge of that element is used/discussed.

7 0
3 years ago
A harbour seal's flipper and a human hand have a very similar structure, but function differently. This is an example
11Alexandr11 [23.1K]

Answer:

Homologous structure

Explanation:

Homologous structures come from same ancestors but have different functions.

4 0
3 years ago
Read 2 more answers
The energy needed to create bonds between two hydrogen molecules is measured in units called __________
igomit [66]
This is called bond energy, or bond enthalpy, and is measured in units of kilojoules per mole (kJ/mol).
5 0
3 years ago
For the following reaction, 89.5 grams of iron are allowed to react with 36.9 grams of oxygen gas. iron (s) oxygen (g) iron(III)
hodyreva [135]

Answer:

122.3 g of Fe₂O₃ is the maximum amount formed

Explanation:

Our reactants for the reaction:

89.5 g of Fe

36.9 g of O₂

We convert the mass of each to moles:

89.5 g of Fe . 1 mol / 55.85 g = 1.60 moles

36.9 g of O₂ . 1mol / 32g = 1.15 moles

The reaction is  4Fe(s) + 3O₂(g) →  2Fe₂O₃ (s)

We determine the limiting reactant:

4 moles of Iron can react with 3 moles of O₂

Therefore 1.60 moles of Iron will react with (1.60 .3) / 4 = 1.2 moles

Oxygen is the limiting reactant; we need 1.2 moles, and we only have 1.15.

Then we work with the stoichiometry again.

3 moles of oxygen can produce 2 moles of Fe₂O₃

1.15 moles of oxygen may produce (1.15 . 2) / 3 = 0.766 moles of Fe₂O₃

We convert the moles to mass: 0.766 mol . 159.7 g /1mol = 122.3 g of Fe₂O₃

4 0
3 years ago
A tank contains 200 gallons of water in which 300 grams of salt is dissolved. A brine solution containing 0.4 kilograms of salt
Nadusha1986 [10]

Answer:

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>

Explanation:

given amount of salt at time t is A(t)

initial amount of salt =300 gm =0.3kg

=>A(0)=0.3

rate of salt inflow =5*0.4= 2 kg/min

rate of salt out flow =5*A/(200)=A/40

rate of change of salt at time t , dA/dt= rate of salt inflow- ratew of salt outflow

dA/dt=2-(A/40)\\\\dA=2dt-(A/40)dt\\\\dA+(A/40)dt=2dt

integrating factor

=e^{\int\limits (1/40) \, dt}

integrating factor =e^{(1/40)t}

multiply on both sides by  =e^{(1/40)t}

dAe^{(1/40)t}+(A/40)e^{(1/40)t} dt =2e^{(1/40)t}t\\\\(Ae^{(1/40)t})=2e^{(1/40)t}t

integrate on both sides

\int\limits(Ae^{(1/40)t})=\int\limits2e^{(1/40)t}dt\\\\(Ae^{(1/40)t})=2*40e^{(1/40)t}+C\\\\A=80+(C/e^{(1/40)t})\\\\A(0)=0.3\\\\0.3=80+(C/e^{(1/40)t}^*^0)\\\\0.3=80+(C/1)\\\\C=0.3-80\\\\C=-79.7\\\\A(t)=80-(79.7/e^{(1/40)t})

b)

after long period of time means t - > ∞

{t \to \infty}\\\\ \lim_{t \to \infty} A_t \\\\ \lim_{t \to \infty} (80)-(79/{e^{(1/40)t}}\\\\=80-(0)\\\\=80

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>
6 0
3 years ago
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