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Zina [86]
2 years ago
9

A liter of milk has a [H] of about 2.51 x 10-7. (You may prefer to think of the hydronium ion concentration, [H3O+], as 2.51 x 1

0-7.) Use the formula for the calculation of pH provided and show each step as you calculate the pH of milk. In order to get full points you must show all the steps you take
Please help!!.​
Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
7 0

Answer:

12-6

Explanation:

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Can anyone fill in the answers?
Arte-miy333 [17]
Hi, P.S. The atomic number will always be the same as the number of protons...

6 0
3 years ago
Which pair of elements can form ionic bonds?
Sindrei [870]

Answer:

E.  potassium (K) and bromine (Br)

Explanation:

An ionic bond is formed between compounds with a large electronegativity difference between them. It is usually between a metal and non-metal.

  • Potassium is a true metal found in group 1 on the periodic table.
  • Bromine is a highly electronegative non-metal which is a halogen.
  • Potassium will lose one of its electrons which will be gained by the Bromine.
  • The electrostatic attraction between the two species will cause the ionic bond to form.
  • The ability of one specie willing to lose electron and the other gaining, is the main bed rock of ionic bonding.
3 0
3 years ago
Read 2 more answers
Noble gases are the least reactive elements on the periodic table.<br> A. True<br> B. False
Nezavi [6.7K]
The answer is A. True
7 0
3 years ago
Read 2 more answers
At 25 °C, the equilibrium partial pressures for the following reaction were found to be PA = 8.00 atm, PB = 5.40 atm, PC = 6.90
Yuliya22 [10]

<u>Answer:</u> The standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol

<u>Explanation:</u>

For the given chemical equation:

A(g)+2B(g)\rightleftharpoons C(g)+D(g)

The expression of K_p for the given reaction:

K_p=\frac{p_C\times p_D}{p_A\times (p_B)^2}

We are given:

p_A=8.00atm\\p_B=5.40atm\\p_C=6.90atm\\p_D=5.90atm

Putting values in above equation, we get:

K_p=\frac{6.90\times 5.90}{8.00\times (5.40)^2}\\\\K_p=0.174

To calculate the standard Gibbs free energy, we use the relation:

\Delta G^o=-RT\ln K_p

where,

\Delta G^o = standard Gibbs free energy

R = Gas constant = 8.314J/K mol

T = temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 0.174

Putting values in above equation, we get:

\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (0.174)\\\\\Delta G^o=4332.5J/mol=4.33kJ/mol

Hence, the standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol

3 0
3 years ago
Convert the following word equations into chemical equations using the correct
Alex17521 [72]

Answer:

Below.

Explanation:

1.   Al2(SO4)^3 (aq) + 6LiOH aql)  ----> 3Li2SO4 (aq) + 2Al(OH)^3 (s)

2.  (NH4)2CO3 (aq) + MgCl2 (aq)  ---->  2(NH4)Cl (aq) +  MgCO3 (s).

7 0
3 years ago
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