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Pavel [41]
3 years ago
4

Given log4^3 =0.792 and log4^ 21=2.196 what is log4^7 1.404 1.739 2.773 2.988

Mathematics
2 answers:
GREYUIT [131]3 years ago
6 0

Answer: The correct answer 1.404

Step-by-step explanation:

\log4^3=0.792

\log4^{21}=2.196

\log4^{21}=\log(4^{3}\times4^{7})=\log4^3+\log4^7=2.196

\log4^7=2.196-\log4^3=2.196-0.792=1.404

The correct value of \log4^7 is 1.404. so the correct option from the given option is 1.404.

PilotLPTM [1.2K]3 years ago
4 0
We have to find log4^7 if we know that log4^3 = 0.792 and log4^21 = 2.196.
We already know that:
log ( x/y ) = log x - log y
log4^21 = log4^( 21 / 3 ) =
= log4^ 21 - log4^ 7 = 2.196 - 0.797 = 1.404
Answer:
A ) 1.404
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