The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is 
<em><u>Solution:</u></em>
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ----- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5
Given line is perpendicular to − 4 x − 3 y = − 5
− 4 x − 3 y = − 5
-3y = 4x - 5
3y = -4x + 5

On comparing the above equation with eqn 1, we get,

We know that product of slope of a line and slope of line perpendicular to it is -1

Given point is (-1, -2)
Now we have to find the equation of line passing through (-1, -2) with slope 
Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1



Thus the required equation of line is found
Step-by-step explanation:
- 3x+5y=7b equation 1
- 2x+4y=1
2x=-4y+1
- x=(-4y+1)/2
- x=(-4y+1)/2 in equation 1
3×(-4y+1)/2+5y=7b
(-12y+3)/2+5y=7b
(-12y+3+10y)/2=7b
(-12y+3)/2=7b
-12y+3=14b
-12y=14b-3
- y=3-14b/12
- y=3-14b/12 in x=(-4y+1)/2
x=(-4×{3-14b/12}+1)/2
x=(-3+14b)/3+1/2
x=14b/3×1/2
Answer:
q = 15
Step-by-step explanation:
Given
f(x) = x² + px + q , then
f(3) = 3² + 3p + q = 6 , that is
9 + 3p + q = 6 ( subtract 9 from both sides )
3p + q = - 3 → (1)
---------------------------------------
f'(x) = 2x + p , then
f'(3) = 2(3) + p = 0, that is
6 + p = 0 ( subtract 6 from both sides )
p = - 6
Substitute p = - 6 into (1)
3(- 6) + q = - 3
- 18 + q = - 3 ( add 18 to both sides )
q = 15
The sales growth is = $25,000
<h3>The analysis of sales data</h3>
The revenue generated from a business like that of the owner of a bike shop is by multiplying the number of sales and the sales price or average service price.
The sales Revenue for Last Year =$125,000
The Sales Revenue for Current Year = $150, 000
Therefore the sales growth can be gotten by subtracting the current year from the previous year. Which is,
$150, 000 - $125,000 = $25,000
Learn more about revenue here:
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