In this case, we cannot simply take the average speed by
adding the two speeds and divide by two.
What we have to do is to calculate the time required
going to school and the return trip home.
We know that to calculate time, we use the formula:
t = d / v
where,
d = distance = 4.8 km = 4800 m
v = velocity
Let us say that the variables related to the trip going
to school is associated with 1, and the return trip home is 2. So,
t1 = 4800 m / (22.6 m / s)
t1 = 212.39 s
t2 = 4800 / (16.8 m / s)
t2 = 285.71 s
total time, t = t1 + t2
t = 498.1 s
Therefore the total average velocity is:
= (4800 m + 4800 m) / 498.1 s
= 19.27 m / s = 19.3 m / s
Answer:
19.3 m/s
Answer:
the correct answer is: 5
Step-by-step explanation:
i put -5 at first and that was incorrect so then i put 5 and it said that was correct
This is the power of powers law. It states that (a^b)^c is equal to a^b*c.
Answer:
Step-by-step explanation:
<u>Given</u>
- DE = 3x + 2, EF = x + 5, DF = 23
<u>As per segment addition postulate</u>
<u>Substituting values:</u>
- 3x + 2 + x + 5 = 23
- 4x + 7 = 23
- 4x = 16
- x = 4
Answer:
-31 1/3 (answer choice 1)
Step-by-step explanation:
Let's begin by eliminating the fractions. Mult. all four terms by the LCD (8), obtaining:
-f - 6 - 2f = 88. Then -3f = 94, and f = -31 1/3
