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2 years ago

PLEASE HELP!!!!!!!!!!!!! (15 points)

Mathematics

2 answers:

Rainbow [258]2 years ago

8 0

X = -2

Y = 2

Hope this helped

tia_tia [17]2 years ago

3 0

The asymptotes are:

X = +2

X = -2

Y = 2

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Please help!!!! I only need to do A not B!!! 8 points!!!!

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2 years ago

Old Grandpa Joe left half his money to his granddaughter and half that amount to his grandson.

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Answer:

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Step-by-step explanation:

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Grandson -- 1/2(1/2 of x)

Brother -- 1/6 of x

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x = 12000

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2 years ago

Write an equation in slope intercept form for the line with slope of 1/5 and y-intercept -8

AlladinOne [14]

Answer:

y = (1/5)x - 8

Step-by-step explanation:

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3 years ago

Read 2 more answers

Using the given information, give the vertex form equation of each parabola.

Amanda [17]

Answer:

The equation of parabola is given by : $(x-4) = \frac{-1}{3}(y+3)^{2}$

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:( $\frac{47}{12}$ ,-3)

The general equation of parabola is given by.

$(x-h)^{2} = 4p(y-k)$ , When x-componet of focus and Vertex is same

$(x-h) = 4p(y-k)^{2}$ , When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

For value of p:

p= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

p= $\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}$

p= $\sqrt{(\frac{1}{12})^{2}}$

p= $\frac{1}{12}$ and p= $\frac{-1}{12}$

Since, Focus is left side of the vertex,

p= $\frac{-1}{12}$ is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p= $\frac{-1}{12}$

$(x-h) = 4p(y-k)^{2}$

$(x-4) = 4(\frac{-1}{12})(y+3)^{2}$

$(x-4) = \frac{-1}{3}(y+3)^{2}$

8 0

2 years ago