Answer:
The maximum is at (1,3)
Step-by-step explanation:
The maximum value of the function is at the vertex
The maximum is at (1,3)
Answer:
Set up your height equation, then factor or use quadratic formula to find when h(t)=0
Step-by-step explanation:
Your equation will be -16t^2+vt +h where v is the initial velocity and h is the starting height. Now either factor or quadratic equation, whichever is easier for you.
Remember that the ball is on the ground when h(t)=0 since that is the height. There will be two zeros, one is a negative number so would be before you kicked the ball, the other one will be when the ball comes back down.
Answer:
10 units
Step-by-step explanation:
Given data
P = (3, 1) and Q = (-3, -7)
x1=3
y1=1
x2= -3
y2= -7
The expression for the distance between two coordinate is
d=√((x_2-x_1)²+(y_2-y_1)²)
Substitute
d=√((-3-3)²+(-7-1)²)
d=√((-6)²+(-8)²)
d=√36+64
d=√100
d=10 units
Hence the distance is 10 units
We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a <span>standard basketball is 4.77 in
</span>
<span>the distance between the ball and the rim is equal to
</span>radius of a basketball rim minus radius of a a standard basketball
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>
</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in
the answer is
4.23 in
