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3 years ago

Solve the above que no. 55

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

4 0

Answer:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

2) $\left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)$ $\tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}$

3) $\left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)$

4) $\left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)$ $\sin^{2}A+\cos^{2}A = 1$

5) $\frac{1}{\sin^{2}A\cdot \cos^{2}A}$

6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

Step-by-step explanation:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

2) $\left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)$ $\tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}$

3) $\left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)$

4) $\left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)$ $\sin^{2}A+\cos^{2}A = 1$

5) $\frac{1}{\sin^{2}A\cdot \cos^{2}A}$

6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

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CaHeK987 [17]

% means out of 100 so 1%=1/100

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(3*30)/1 or 90/1 or 90 cents

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Lila collected the honey from 3 of her beehives. From the first hive she collected 2/3 gallon of honey. The last two hives yield

slamgirl [31]

Answer:

a). Lila collected 7/6 gallon in all.

b). She used for baking 5/12 gallon.

c) was left 1/3 gallon of honey

D) She used 3/8lb flour to make the brownies.

Step-by-step explanation:

a). Lila collected 7/6 gallon in all.

$\frac{2}{3} +\frac{1}{4} +\frac{1}{4} \\$

LCM=3*4=12

$\frac{8+3+3}{12}=14/12=7/6$

b). She used for baking 5/12 gallon.

She had 7/6 gallon of honey. She used 3/4 gallon for baking. To know how much honey was left, you have to substract 3/4 gallon from the total available honey 7/6 gallon.

$\frac{7}{6}-\frac{3}{4}$

You need to find LCM to substract fractions with different denominator:

LCM=12

$\frac{14-9}{12}=\frac{5}{12}$

c) was left 1/3 gallon of honey

To know how much honey was left you need to substract from the initial quantity of honey that is 3/4 gallon, the quantities used for baking, that are 1/6 gallon and 1/4 gallon.

Less common multiple: 12

$\frac{3}{4}-\frac{1}{6} -\frac{1}{4}$

We use LCM 12 to substract:

$\frac{9-2-3}{12}=\frac{4}{12} =\frac{1}{3}$

D) She used 3/8lb flour to make the brownies.

You know she used 1/2 lb flour to make the bread and to make cookies 1/8 more. So you need to do following math:

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She used 5/8 to make cookies and she used 1/4 more to make cookies than brownies, then you have to do following math;

$\frac{5}{8}-\frac{1}{4}=\frac{5-2}{8}=\frac{3}{8}$

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3 years ago

What is the magnitude of the resultant vector of z-y?

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For this case what we should do is take into account the following vectors:

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We must find the following subtraction of vectors:

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Subtracting component to component we have:

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option B

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What is 1 whole minus 7/12

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The register contains 8 number of $20 bills and 13 number of $100 bills.

<h3>What is termed as the linear equation in two variables?</h3>

A linear equation in two variables is one that is written in the form ax + by + c=0, where a, b, and c are real numbers as well as the coefficients of x and y, i.e. a and b, are not equal to zero.

Let 'x' be the of $20 bills.

Let 'y' be of $100 bills.

Total bill = 21

x+y = 21

y = -x+21 ......eq1

Now,

Total price = $1460.

20x + 100y = 1460

Put value of y from eq 1.

20x + 100(-x+21) = 1460

20x-100x+2100=1460

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x=8 (Number of $20 bill)

And,

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Thus, the register contains 8 number of $20 bills and 13 number of $100 bills.

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brainly.com/question/4074386

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The complete question is-

A cash register contains $20 bills and $100 bills with a total value of $1460. If there are 21 bills total, then how many of each does the register contain?

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