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marissa [1.9K]
3 years ago
12

Parking Lot A has twice as many cars as Parking Lot B. After 10 cars draw away from Parking lot A, and 13 cars moved from parkin

g lot A to Parking lot B, Parking lots have the same amount of cars. How many cars were there in each Parking Lot?
PLEASE HELP ASAP
Mathematics
2 answers:
Tcecarenko [31]3 years ago
6 0

Answer:

a=72 and b=36

Step-by-step explanation:

A=2B

A-10-13=B+13

OlgaM077 [116]3 years ago
5 0

Answer:

Number of cars in Parking lot A = 72 and in Parking Lot B = 36

Step-by-step explanation:

Let the number of cars in parking A is = A and in parking B is = B

Now we will make the equations

" Parking lot A has twice as many cars as Parking lot B"

A = 2B  ------(1)

"After 10 cars draw away form parking lot A, and 13 cars moved from parking lot A to parking lot B then both the lots have same amount of cars."

A - 10 - 13 = B + 13

A - 23 = B +13

A = B + 13 + 23

A = B + 36 ------(2)

Now we equate the values of A in both the equations

2B = B + 36

2B - B = 36

B = 36

From equation 1

A = 2B

A = 2×(36) = 72 cars

Therefore, number of cars in Parking lot A = 72 and in Parking Lot B = 36

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Minchanka [31]

Answer: 6 km to 22 km !

Step-by-step explanation:

the distances from the school mall to bus station could be, in the worst case, 14+8=22 km apart, and in the best case 14-8=6 km apart

so the range is 6 km to 22 km !

8 0
2 years ago
Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000 If we record the se
lys-0071 [83]

Answer:

The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000

Sample of 40

Shape approximately normal

Mean 350000

Standard deviation s = \frac{160000}{\sqrt{40}} = 25298

The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

5 0
3 years ago
Read 2 more answers
The sum of two confescutive integers is at least 46. What is the least possibly pair of integers?
dezoksy [38]
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.

1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46

So we have two possibilities: either #2 or #4. Find least possible pair of integers.

x= first integer
x+1= second integer

x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5

Answer:
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Hope this helps! :)
3 0
3 years ago
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Vinil7 [7]

Answer:

<h3>The answer is - 6</h3>

Step-by-step explanation:

f(X)=3x-12

To find f(2) substitute the value in the bracket which is 2 into f(x)

That's

f(2) = 3(2) - 12

= 6 - 12

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Hope this helps you

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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