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marissa [1.9K]
3 years ago
12

Parking Lot A has twice as many cars as Parking Lot B. After 10 cars draw away from Parking lot A, and 13 cars moved from parkin

g lot A to Parking lot B, Parking lots have the same amount of cars. How many cars were there in each Parking Lot?
PLEASE HELP ASAP
Mathematics
2 answers:
Tcecarenko [31]3 years ago
6 0

Answer:

a=72 and b=36

Step-by-step explanation:

A=2B

A-10-13=B+13

OlgaM077 [116]3 years ago
5 0

Answer:

Number of cars in Parking lot A = 72 and in Parking Lot B = 36

Step-by-step explanation:

Let the number of cars in parking A is = A and in parking B is = B

Now we will make the equations

" Parking lot A has twice as many cars as Parking lot B"

A = 2B  ------(1)

"After 10 cars draw away form parking lot A, and 13 cars moved from parking lot A to parking lot B then both the lots have same amount of cars."

A - 10 - 13 = B + 13

A - 23 = B +13

A = B + 13 + 23

A = B + 36 ------(2)

Now we equate the values of A in both the equations

2B = B + 36

2B - B = 36

B = 36

From equation 1

A = 2B

A = 2×(36) = 72 cars

Therefore, number of cars in Parking lot A = 72 and in Parking Lot B = 36

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What is 3(x-1)<12 or x+7>10
Otrada [13]

Simplifying

3[x + -1] = 12

Reorder the terms:

3[-1 + x] = 12

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2 years ago
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MA_775_DIABLO [31]

Answer:

a. y = 250 (0.4)^x

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Step-by-step explanation:

The equation can be modeled as a geometric sequence, where the first term is 100 and the common ratio is 0.4.

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This can also be simplified to:

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When x = 9:

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