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kipiarov [429]
3 years ago
5

The average cell phone bill per year was $650 in 2009. If the average cost each year is about 109.2% of the previous year (9.2%

increase), what will a person pay total for a cell phone for 2009-2018? (Round to nearest dollar.) Question 9 options: $8535 $6500 $7098 $9970 Save
Mathematics
2 answers:
slega [8]3 years ago
7 0

Answer:

$ 8535

Step-by-step explanation:

Given,

The average cell phone bill in 2009 = $ 650,

Since, the average cost each year is about 109.2% of the previous year,

Thus, there is a GP, that shows the average cell phone bill of every year,

That having first term, a = 650,

Common difference, d = 109.2 % = 1.092,

Thus, the total cell phone bill for 2009-2018 = Sum of the 9 terms of the above G.P.

S_{n}=\frac{a(r^n-1)}{r-1}

S_{9}=\frac{650(1.092^9-1)}{1.092-1}

=8534.95058244

\approx 8535

Hence, The person will pay approximately $ 8535 for 2009 - 2018.

First option is correct.

galina1969 [7]3 years ago
3 0
I believe the answer is $709.8 but $7098 seems the closest
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