3 years ago

F(-2){3x^2-1,x<1}{x+2,x_>+8

1 answer:

4 0

f(x) = 3x² - 1
f(-2) = 3(-2)² - 1
f(-2) = 3(4) - 1
f(-2) = 12 - 1
f(-2) = 11

f(x) = x < 1
f(-2) = -2 < 1

f(x) = x + 2
f(-2) = -2 + 2
f(-2) = 0

f(x) = x ≥ 8
f(-2) = -2 ≠ 8

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