Haileys work is correct so B should be the right answer
The center is at origin O(0,0).
If it contains the point, P(-8,6), then the radius r is, by Pythagoras theorem,
r=sqrt((-8)^2+6^2)=10
The general equation of a circle at centre (xc,yc) with radius r is given by
(x-xc)^2+(y-yc)^2=r^2
Substituting r=10, (xc,yc)=(0,0)
the resulting equation is therefore
(x-0)^2+(y-0)^2=10^2
or simply
x^2+y^2=100
4x/9 = 5/27
Multiply both sides by 9 to give
4x = 45/27
Now multiply both sides by 27 to give
108x = 45
Now divide both sides by 108 to give
x = 45/108
Reduce the fraction to give
x = 5/12
Answer:
(2x + 3)(x - 2)
Step-by-step explanation:
use FOIL
First, Outside, Inside, Last
2x x x = 2x²
2x x -2 = -4x
3 x x = 3x
3 x -2 = -6
2x² - 4x + 3x - 6
Depends on what place you are rounding to. you would usually drop them
