Okay you have 2 sum unknow lets call them X+Y
so X+Y=33, 4X=108
Get X by it self then plug it in 4X=108
X=-Y+33
4(-y+33)= 108
-4y+132=108 Then subtract the 132
-4y=-24 Y=6 then to find X subtract 33-6=27
Y=6 X=27 if you check it works out
Answer:
174 in²
Step-by-step explanation:
(A1)= 9(5)= 45 in²
(A2)= 3(5)=15 in²
(A3)= 3(5)=15 in²
(A4)= 9(3)= 27 in²
(A5)= 9(5)= 45 in²
(A6)= 9(3)= 27 in²
(totalA)= 45+15+15+27+45+27= 174 in²
1.
15 × 12× 20
3600
2.
2×2×3
12
3.
24.3×8.5×9.7
2003.535
Answer:
Therefore x=9
Step-by-step explanation:
Give that,
log x+ log (x-3) = log 54
log x(x-3) =log 54 [
]
x(x-3) = 54
Now expand the above equation to get a quadratic equation
x²-3x=54
⇒x²-9x+6x-54=0
⇒x(x-9)+6(x-9)=0
⇒(x-9)(x+6)=0
⇒x-9=0 or, x+6=0
⇒x=9,-6
Now putting x= -6 in the given expression,
log(-6)+log(-6-9)=log 54.
Since log (-6) does not exist.
Therefore x=9