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2 years ago

15

Help plz I don't wanna fail my diagnostic I already have full on C's I only have 1 week left I really need to go to the next gra

de :)

1 answer:

tigry1 [53]2 years ago

3 0

Answer:

hundreds

Step-by-step explanation:

You might be interested in

Sandeep has twice as much as sonia. together they have rs 150. how much does sonia have

Inga [223]

let sonia has the (x)

Sandeep would have twice as much as Sonia so (2x)

together they'd have 150.

so, x+2x=150

solve for X

3x=150

X=150/3

So x=50 is what Sonia has,

and Sandeep would have 2(50) =100

5 0

3 years ago

The average age of online consumers a few years ago was 24.1 years. As older individuals gain confidence with the Internet, it

love history [14]

Answer:

The correct option is (C).

Step-by-step explanation:

A null hypothesis is a sort of hypothesis used in statistics that intends that no statistical significance exists in a set of given observations.

It is a hypothesis of no difference.

It is typically the hypothesis a scientist or experimenter will attempt to refute or discard. It is denoted by H₀.

Whereas the alternative hypothesis is a contradicting statement tot he null hypothesis. It is denoted by Hₐ.

In this case we need to test whether the average age of online consumers has increased or not.

From previous data we know that the average age of online consumers a few years ago was 24.1 years.

A one-sample mean test can be used to determine whether the mean age has increased or not.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The average age of online consumers is 24.1 years, i.e. <em>μ</em> = 24.1.

<em>Hₐ</em>: The average age of online consumers is more than 24.1 years, i.e. <em>μ</em> > 24.1.

Thus, the correct option is (C).

6 0

3 years ago

Solve for y. 13 = 6 + y

kvv77 [185]

The answer is 7
13-6 is 7

5 0

3 years ago

Read 2 more answers

In a recent year, a poll asked 2362 random adult citizens of a large country how they rated economic conditions. In the poll,

Harman [31]

Answer:

a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

c) $\alpha=0.01$

Step-by-step explanation:

<em>Data given and notation </em>

n=2362 represent the random sample taken

X represent the people who says that they would watch one of the television shows.

$\hat p=\frac{X}{n}=0.22$ estimated proportion of people rated as Excellent/Good economic conditions.

$p_o=0.24$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest) <em> </em>

<em>Concepts and formulas to use </em>

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:

Null hypothesis: $p=0.24$

Alternative hypothesis: $p \neq 0.24$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a: Test the hypothesis

<em>Check for the assumptions that he sample must satisfy in order to apply the test </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

<em>Calculate the statistic</em>

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28$

The confidence interval would be given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The critical value using $\alpha=0.01$ and $\alpha/2 =0.005$ would be $z_{\alpha/2}=2.58$ . Replacing the values given we have:

$0.22 - (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.198$

$0.22 + (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.242$

So the 99% confidence interval is given by (0.198;0.242).

Part b

<em>Statistical decision </em>

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided is $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

Part c

The confidence level assumed was 99%, so then the signficance is given by $\alpha=1-confidence=1-0.99=0.01$

6 0

2 years ago

what is the answer please help me

kenny6666 [7]

I can’t see the entire question, but i’m going to go out on a limb and say it’s divide, y-value, x-value

3 0

3 years ago