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scoundrel [369]
4 years ago
14

A plane flies round-trip to Philadelphia. It flies to Philadelphia at 220 miles per hour and back home with a tailwind at 280 mi

les per hour. If the total trip takes 6.5 hours, how many miles does the plane fly round-trip? 560 miles 800.8 miles 1,300 miles 1,601.6 miles
Mathematics
1 answer:
dem82 [27]4 years ago
6 0
<span> 1,601.6 miles is correct</span>
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Giving 40 Points...need help as soon as possible
PIT_PIT [208]
The <u>correct answers</u> are:

The <span><u>first system</u> </span>matches with (-4, 5);
The <u>second system</u> matches with (2, 2); 
The <u>third sys</u><span><u>tem</u> </span>matches with (-1, -3);
The <u>fourth system</u> matches with (3, 4);
The <u>fifth system</u> matches with (2, -1); and 
<span>The <u>sixth system</u> matches with (-5, 6).</span>

<span>Explanation:</span>

The <u>sixth system</u> is the easiest one to find.  We are given the value of x and the value of y in the equations: x=-5 and y=6.

For all other systems, we must solve the system.  For the <u>first system</u>:
\left \{ {{2x-y=-13} \atop {y=x+9}} \right.

Since we have the y-variable isolated in the second equation, we will use substitution.  We substitute this value in place of y in the first equation:
2x-y=-13
2x-(x+9)=-13

Distributing the subtraction sign,
2x-x-9=-13

Combining like terms:
x-9=-13

Add 9 to each side:
x-9+9=-13+9
x=-4

Substitute this into the second equation:
y=x+9
y=-4+9
y=5

<u>The coordinates (-4, 5) represent the solution point.</u>

For the <u>second system</u>:
\left \{ {{3x+2y=10} \atop {6x-y=10}} \right.

We can make the coefficients of x the same and use elimination.  To do this, we will multiply the first equation by 2:
<span>\left \{ {{2(3x+2y=10)} \atop {6x-y=10}} \right. \\ \\ \left \{ {{6x+4y=20}  \atop {6x-y=10}} \right.

Since the coefficients of x are now the same, we can cancel it.  They are both positive, so we subtract:
\left \{ {{6x+4y=20} \atop {-(6x-y=10)}} \right. \\ \\5y=10

Divide both sides by 5:
5y/5=10/5
y=2

Substitute this into the second equation
6x-y=10
6x-2=10

Add 2 to each side:
6x-2+2=10+2
6x=12

Divide both sides by 6:
6x/6 = 12/6
x=2

<span><u>The coordinates (2, 2) represent the solution to this system.</u></span>

<span>For the <u>third system</u>:</span>
\left \{ {{4x-3y=5} \atop {3x+2y=-9}} \right.

We can make the coefficients of x the same by multiplying the first equation by 3 and the second by 4:
\left \{ {{3(4x-3y=5)} \atop {4(3x+2y=-9)}} \right. \\ \\ \left \{ {{12x-9y=15} \atop {12x+8y=-36}} \right.

Since the coefficients of x are the same, we can cancel them.  Since they are both positive, we will subtract:
\left \{ {{12x-9y=15} \atop {-(12x+8y=-36)}} \right. \\ \\-17y=51

Divide both sides by -17:
-17y/-17 = 51/-17
y=-3

Substitute this into the first equation:
4x-3y=5
4x-3(-3)=5
4x--9=5
4x+9=5

Subtract 9 from each side:
4x+9-9=5-9
4x=-4

Divide each side by 4:
4x/4 = -4/4
x=-1

<u>The coordinates (-1, -3) represent the solution of the third system..</u>

For the <u>fourth system</u>:
\left \{ {{x+y=7} \atop {x-y=-1}} \right.

Since the coordinates of x are the same and both are positive, we can cancel x by subtracting:
\left \{ {{x+y=7} \atop {-(x-y=-1)}} \right. \\ \\2y=8

Divide both sides by 2:
2y/2 = 8/2
y=4

Substitute this into the first equation
x+y=7
x+4=7

Subtract 4 from each side:
x+4-4=7-4
x=3

<u>The coordinates (3, 4) represent the solution to the fourth system.</u>

For the <u>fifth system</u>:
\left \{ {{y=3x-7} \atop {y=2x-5}} \right.

Since y is isolated in each equation, we can set them equation to each other:
3x-7=2x-5

Subtract 2x from each side:
3x-7-2x=2x-5-2x
x-7=-5

Add 7 to each side:
x-7+7=-5+7
x=2

Substitute this into the first equation:
y=3x-7
y=3(2)-7
y=6-7
y=-1

<span><u>The coordinates (2, -1) represent the solution to the fifth system.</u></span> </span>
7 0
3 years ago
A hot air balloon can hold up to 300 pounds of weight. The balloon's pilot weighs 140 pounds. How many 20-pound bags of sand (b)
Orlov [11]

Answer:

8, 5, 0 (B, C, D)

Step-by-step explanation:

okay so in order to solve this, first you would do 300-140 since the limit is 300 and 140 is already occupied. 300-140=160. Next, to find the number of 20-pound bags that can fit, you would do 160/20 or just 20b<_160 (<_ is less than or equal to). b<_ 8, therefore you could have anything ranging from 0b-8b. You cannot have a negative number of bags, that is just not possible, and with 10 bags, you surpass the weight limit by 40 pounds.

7 0
3 years ago
4x^2-13x+10 x method<br><br><br><br>​
Afina-wow [57]

Answer:

4x2 − 3x = 0

Factorization:

x(4x − 3) = 0

Solutions based on factorization:

x = 0   ⇒   x1 = 0

4x − 3 = 0   ⇒   x2 = 34 = 0.75

hope this helps if wrong sorry

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What does 9/5 + 14/12 equal
fenix001 [56]

Answer:

53/50

Step-by-step explanation:

9/15 + 14/12

Simplify.

9/15 + 7/6

Make denominators equal.

54/90 + 105/90

Add fractions since denominators are equal.

159/90

Simplify.

= 53/50

7 0
3 years ago
Write an equation of the line from the table
stellarik [79]

Answer:

y=x+6

Step-by-step explanation:

x to y is always add 6.

This is why the equation is y=x+6

Hope this helps :)

4 0
3 years ago
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