8 to 1 i think not saying its the answer though i think it is
First picture
ABC is a triangle so
m<A +m<B+m<C = 180
6x - 1 + 20 + x + 14 = 180
7x + 33 = 180
7x = 180 - 33
7x = 147
x = 147/7
x = 21
m<A = 6x - 1 = 6(21) - 1 = 125
m<C = x + 14 = 21 + 14 = 35
answer:
m<A = 125
m<C = 35
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second picture
ABC is a triangle so
m<A +m<B+m<C = 180
48 + 6x - 28 + 2x = 180
8x + 20 = 180
8x = 180 -20
8x = 160
x = 160/8
x = 20
m<B = 6x - 28 = 6(20) - 28 = 120 - 28 = 92
m<C = 2x = 2(20) = 40
answer:
x = 20
m<B = 92
m<C = 40
In this problem, you are looking at a pair of similar trapezoids. So we must be looking for a ratio between a side in the smaller trapezoid and the corresponding side in the bigger trapezoid. We are given the lengths of AB and EF, which we can use to find this ratio.
But before we do anything we must convert units so that all units are the same. Let's convert the 60 feet into inches. 60 feet is 720 inches.
Next, set up the ratio I mentioned earlier. If we set up the ratio so that it is smaller:larger, we would get 4:720, which simplifies to 1:180. Basically what this ratio says is that every 1 inch in the smaller trapezoid corresponds to 180 inches in the bigger trapezoid. Now we can use this ratio to find the lengths of the sides in the bigger trapezoid. Just multiply all the lengths of the smaller trapezoid by 180 to get the lengths for the bigger trapezoid. Finally, when we have all our side lengths, divide them all by 12 (because 12 inches in 1 foot) to get the measurements in feet.
From here, I'll let you find the total length yourself.
Answer:
Amount left in bag one = 20kg
Amount left in bag 2 = 40 kg
Step-by-step explanation:
We are told that Two bags had 50 kilograms of sugar each.
Let first bag be x and second bag be y.
Now, we are told that After taking out 3 times as much sugar from bag one than bag two, bag one had half as much sugar left as bag two.
Thus, amount taken from bag one is;
3a and amount taken from bag two is a.
Amount left in bag 1 is;
50 - 3a while amount left in bag 2 is 50 - a.
Since bag one had half as much sugar left as bag two, then;
50 - 3a = ½(50 - a)
50 - 3a = 25 - 0.5a
50 - 25 = 3a - 0.5a
25 = 2.5a
a = 25/2.5
a = 10
Thus;
Amount left in bag 1 = 50 - 3a = 50 - 3(10) = 50 - 30 = 20 kg.
Amount left in bag 2 = 50 - a = 50 - 10 = 40 kg
