Question

2 1/4(4x-1)=1 3/5(1+4x)?? I need help with this problem. Thanks!!

Answer 1

Solving $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$ we get $x=\frac{77}{52}$

Step-by-step explanation:

We need to solve the problem: $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$

Solving:

$2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)\\\frac{9}{4}(4x-1)=\frac{8}{5}(1+4x)\\9x-\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}$

Add 9/4 on both sides:

$9x-\frac{9}{4}+\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}+\frac{9}{4}$

$9x=\frac{8}{5}+\frac{9}{4}+\frac{32x}{5}\\9x-\frac{32x}{5}=\frac{8}{5}+\frac{9}{4}\\\frac{9x*5-32x}{5}=\frac{8*4+9*5}{20}\\\frac{45x-32x}{5}=\frac{32+45}{20}\\\frac{13x}{5}=\frac{77}{20}\\x=\frac{77}{20}\times \frac{5}{13}\\x=\frac{77}{4*13}\\x=\frac{77}{52}$

So, Solving $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$ we get $x=\frac{77}{52}$

Keywords: Solving Fractions

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