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2 years ago

PLEASE HELP ME I AM STUCK AND I HAVE A HEADACHE I WILL GIVE BRAINLIST!!!!!!!

Mathematics

1 answer:

professor190 [17]2 years ago

3 0

First, we can eliminate d(x) because we can see it's a linear line. We can also eliminate a(x) because it's also a linear line. Both b(x) and c(x) have an asymptote. on b(x) you can see that x = 3 is the asymptote. For c(x) if it's graphed, it has a horizontal asymptote at y = -1.

Hope this helps!

You might be interested in

What is -6x-7x? i don't understand how to do it please teach me how to solve this

Aloiza [94]

How to do Negative Addition

Negative Addition is almost like Positive addition. The only catch in Negative Addition is that it is like subtracting. Let me make this clearer. If you draw a number line, with the positives and the Negatives, it will look somewhat like this. (Attachment down below). As you see, the Positives are increasing to the right, but the Negatives are increasing to the left.

When you do addition, you increase right? Like you have 8+4 which is 12. In positive addition you increase to the right, (look on number line). So, if you reverse it to -8+4 you would have to increase to the right, not the left. -8+4 is not -12 because when you add, you increase not decrease. (-12 is smaller than -8 and 4).

So that means -8+4 is -4.

Trick: Subtraction

Another way to think about it is replacing the addition sign to a minus sign then make the negative go away. So, we get 8-4 which is 4. And then we put the negative sign at the 4, so we get -4.

If you don't understand this, plz tell me

Solving your Problem

1) Take out the X to make it simple (Later we are going to add it back

2)Draw a number line to help you (Optional)

3) Use the subtraction Trick (Optional, but imma use it)

4) 6-7= -1 (Make that positive)

5) The answer is 1x

I hope this helped if you want here is some practice questions to get you ready and comfortable with this skill

Ps. Brianlist Would help

Practice Work~

1) -3+2

2) -10+9

3)-150+100

4) 60+-200

3 0

1 year ago

If point P partitions the segment AB in a 1:2 ratio, where is point P located?

Gwar [14]

If AP and PB are in a 1:2 ratio, it means that PB is twice AB.

So, AP must fit three times into AB, meaning that P must be at one third of the way between A and B.

6 0

3 years ago

A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 for g and 3.14 for π. If you ente

OLEGan [10]

To answer the question above, we will have to use some calculus approach to this problem.

volume of sphere = (4/3)(pi)(radius^3) = (4/3)(pi)(9^3) = 972pi 
mass = (density)(volume) = (972pi)(1,000) = 972,000pi 
force = (mass)(acceleration or gravity here) = (972,000pi)(9.8) = 9,525,600pi 
work = (force)(distance) = (9,525,600pi)(4.5) = 42,865,200pi J

I hope my answer helped you with your problem

6 0

2 years ago

A poll of 793 adults aged 18 or older asked about purchases that they intended to make for the upcoming holiday season. One of t

Ira Lisetskai [31]

Answer:

(0.5793, 0.6363)

Step-by-step explanation:

Given that a poll of 793 adults aged 18 or older asked about purchases that they intended to make for the upcoming holiday season. One of the questions asked about what kind of gift they intended to buy for the person on whom they would spend the most. Clothing was the first choice of 482 people.

i.e. sample proportion p= $\frac{482}{793} =0.608$

$q=1-p = 0.392$

Std error of p = $\sqrt{pq/n} =0.0173$

For 90% Z crtiical = 1.645

Hence margin of error = 1.645 * std error = 0.0285

Confidence interval 90%

= proportion ±margin of error

= $(0.5793, 0.6363)$

3 0

3 years ago

A fair die is rolled 12 times. the number of times an even number occurs on the 12 rolls has

bonufazy [111]

Answer:

Step-by-step explanation:

For a fair die, there are six likely options; 1, 2, 3, 4, 5, and 6

the probability of a even number is 3/6 = 0.5

Since the results of the die roll is independent and each trial is mutually exclusive, the distribution to explain the probability of occurrence will follow a binomial distribution such that n is the number of trials

x = number of successful throws

therefore for a Binomial distribution where

P(X =x) = nCx . P^x . (1-P)^ (n-x)

since p = 0.5, and n = 12, the distribution follows

P(X = x) = 12Cx . 0.5^x . (1 - 0.5)^(12- x)

= 12Cx . 0.5^x . 0.5)^(12- x)

where x = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

since we are interested in the probability of the number of times an even number occurs

it can occur either as P(X = 0), P(X =1), P(X =2), P(X =3), P(X =4), P(X =5), P(X =6), P(X =7), P(X =8), P(X =9), P(X =10), P(X =11), and P(X =12)

For no even number in 12 rolls,

P(X = 0) = 12C0 . 0.5^0 . 0.5^(12- 0) = 0.000244

For one even number in 12 rolls,

P(X = 1) = 12C1 . 0.5^1 . 0.5^(12- 1) = 0.002930

For two even number in 12 rolls,

P(X = 2) = 12C2 . 0.5^2 . 0.5^(12- 2) = 0.016113

For three even number in 12 rolls,

P(X = 3) = 12C3 . 0.5^3 . 0.5^(12- 3) = 0.053711

For four even number in 12 rolls,

P(X = 4) = 12C4 . 0.5^4 . 0.5^(12- 4) = 0.120850

For five even number in 12 rolls,

P(X = 5) = 12C5 . 0.5^5 . 0.5^(12- 5) = 0.193359

For six even number in 12 rolls,

P(X = 6) = 12C6 . 0.5^6 . 0.5^(12- 6) = 0.225586

For seven even number in 12 rolls,

P(X = 7) = 12C7 . 0.5^7 . 0.5^(12- 7) = 0.193359

For eight even number in 12 rolls,

P(X = 8) = 12C8 . 0.5^8 . 0.5^(12- 8) = 0.120850

For nine even number in 12 rolls,

P(X = 9) = 12C9 . 0.5^9 . 0.5^(12- 9) = 0.053711

For ten even number in 12 rolls,

P(X = 10) = 12C10 . 0.5^10 . 0.5^(12- 10) = 0.016113

For eleven even number in 12 rolls,

P(X = 11) = 12C11 . 0.5^11 . 0.5^(12- 11) = 0.002930

For twelve even number in 12 rolls,

P(X = 12) = 12C12 . 0.5^12 . 0.5^(12- 12) = 0.000244

Final test summation[P(X)] = 1

i.e.

P(X = 0) + P(X =1) + P(X =2) + P(X =3) + P(X =4) + P(X =5) + P(X =6) + P(X =7) + P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) = 1

Hence since 0.000244 + 0.002930 + 0.016113 + 0.053711 + 0.120850 + 0.193359 + 0.225586 + 0.193359 + 0.120850 + 0.053711 + 0.016113 + 0.002930 + 0.000244 = 1.000000,

the probability value stands

7 0

2 years ago