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katrin2010 [14]
4 years ago
15

4) Will Mark Brainliest + 10 points!

Mathematics
1 answer:
sammy [17]4 years ago
3 0
Fifth term / second term = a1r^4 / a1r = r^3 = 768 / -12 = -64

so r = -4  and first term a1 =  -12/-4 = 3  

answer is  3*(-4)^(n-1)

Its C
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Suppose a rollerblade racer finished a 132 meter race in 18 seconds. What is the average speed of the rollerblade racer?
fomenos
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the answer on a calculator is 7.33333...
8 0
3 years ago
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Javier works in a photo lab and needs to make a reduced copy of a photograph that is 8 inches long. The customer wants the copy
Scrat [10]

Answer:

Javier should not press the button five time.

Step-by-step explanation:

The given scenario says that Javier claimed that pressing the button 5 times would be enough to fulfill the customer's request. So, lets check that.

We will start at 8 inches.

Press once, 8-0.12*8=7.04 inches.

Pressing again, we get 7.04-.12*7.04=6.1952 inches.

Again pressing we get 6.1952-.12*6.1952 = 5.451776 inches.

Again we get 5.451776-.12*5.451776 =4.79756288 inches.

Again we get 4.79756288-.12*4.79756288= 4.221855334 inches.

We can clearly see here that pressing 4 or 5 times does not get 4.5 inches exactly as claimed by Javier.

Therefore, Javier claim is not right and his boss is right.

5 0
4 years ago
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Solve 0 = 4x2+12x+9.
mars1129 [50]

Answer:

Exact Form:

x = − 3/ 2

Decimal Form:

x = − 1.5

Mixed Number Form:

x = − 1  1/ 2

Step-by-step explanation:

4 0
3 years ago
What is the interest due at maturity for a $1800 note borrowed for 2.5 years at a rate of 14.0%
vesna_86 [32]
This is a hard question good luck
5 0
3 years ago
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A manager records the repair cost for 4 randomly selected TVs. A sample mean of $88.46 and standard deviation of $17.20 are subs
WINSTONCH [101]

Answer:

a) The critical value is z = 2.575.

b) The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha. This is our critical value

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

a. Find the critical value that should be used in constructing the confidence interval.

The critical value is z = 2.575.

b. Construct the 99% confidence interval. Round your answer to two decimal places.

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. So, in this problem

M = 2.575*\frac{17.20}{\sqrt{4}} = 22.15

The lower end of the interval is the mean subtracted by M. So it is 88.46 - 22.15 = $66.31

The upper end of the interval is the mean added to M. So it is 88.46 - 22.15 = $110.61

The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

5 0
3 years ago
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