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liq [111]
3 years ago
5

PLEASE HELP?!?!?!

Mathematics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

c. In 2 seconds, the commuter train travels 120 feet.

Step-by-step explanation:

Given

The attached graph

Required

What does x-coordinate of 2 represents

Represent this coordinate with (x,y)

From the graph:

x = 2 when y = 120

Note that:

x = time and y = distance

So:

(x,y) = (2,120)

Which means:

At 2 seconds, the train has travelled a distance of 120ft

<em>From the list of options, (c) is correct</em>

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Answer:

A=pir²

Step-by-step explanation:

pi=3.14

r=15

r²=15²=225

A=225× 3.14= 706.5

3 0
2 years ago
2n + 3 and 12n - 6 what's the answer and an equivalent
Annette [7]

Answer:

9/10

Step-by-step explanation:

2n+3=12n-6

3=12n-2n-6

3=10n-6

10n=3+6

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3 0
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2 mi. yd. I'm confused​
dybincka [34]

Answer && Step-by-step explanation:

Obtain yards by multiplying miles by 1760

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6 0
3 years ago
If you use your office computer 40 hours per week, and do not unplug the computer when it is not in use, how much carbon dioxide
dangina [55]
If you use a laptop:  9.25; a desktop with a CRT monitor:  55.51; a desktop with an LCD monitor:  46.26.

A laptop that is plugged up and turned off uses 0.001kw/hr of energy.  Each kwh of energy produces, on average, 1.39 lbs of CO2.  There are 24*7=168 hours in the week; subtract the 40 hour work week from this and we have 128 hours a week for 52 weeks a year:
0.001*128*52=6.656*1.39=9.25.

A desktop that is plugged up and turned off uses 0.004kw/hr of energy.  A CRT monitor uses 0.002 kw/hr when turned off.  This means we have:
(0.004*128*52*1.39)+(0.002*128*52*1.39)=55.51.

For a desktop and an LCD monitor, which uses 0.001 kw/hr of energy, we have:
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6 0
4 years ago
Will give brainliest
Galina-37 [17]

The percentage of the radioactive isotope left is 25.0000%.

<h3>What is the half life?</h3>

The half life of a radioactive isotope is the time that will elapse before only half of the number of original isotopes will remain.

Now;

We are told that;

Half life (t1/2) = 55 days

Time taken (t) =  115 days

Ratio of isotope remaining = N/No

Thus;

N/No = (1/2)^t/t1/2

N/No = (1/2)^115/55

N/No = (1/2)^2

N/No =1/4

Hence, the percentage = 1/4 * 100/1 = 25.0000%

Learn more about half life of an isotope:brainly.com/question/16387602

#SPJ1

7 0
2 years ago
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