22 increases by 0.9
24 increases by 4 and 1/2
25 increases by 4.3
Just subtract the number from the number after it to find how to find the next numbers in the sequence
9514 1404 393
Answer:
C
Step-by-step explanation:
You can reflect point x across the origin to find is is just above -1. Adding 3 to that value gives a point just above -1+3 = 2. That's where point C is located.
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<em>Algebraic solution</em>
Algebraically, you can set y = -x +3, and solve for x. That gives you ...
x = 3 -y
Using the relation given at the start:
0 < x < 1
0 < 3 -y < 1 . . . . . substitute for x
Adding y gives ...
y < 3 < y+1
We can separate this into two inequalities:
y < 3, and
3 < y+1
2 < y . . . subtract 1
Now, we have ...
2 < y < 3 . . . . . the location of point C
As you can see, it is much easier to use the number line directly to find the desired point.
Answer:
3/9
Step-by-step explanation:
15/45
divide both sides by a factor of each number; I'll be using 5.
3/9
It didn't have to be 5, I could have used 3, but in that case It wouldn't have been it's simplest form and I would have to divide again by another factor.
Lets say u want an item that originally cost $ 50.....and u get a 25% discount....then u are actually subtracting 25% of the original price.
25% of 50 .....turn the percent to a decimal..." of " means multiply
0.25 * 50 = 12.50.....so u would be subtracting 12.50 from $ 50 for the discounted price which is (50 - 12.5) = 37.5
here is another example...
u want an item that costs $ 90....and it is 25% off.....so u would be subtracting (25% of 90).......u would be subtracting (0.25 * 90) = 22.50 from the original price to arrive at the discounted price.
90 - 22.50 = 67.50...the discounted price
But let me show u something....taking 25% off is the same as paying 75%..
so lets say u want an item that costs $ 60....and u get a 25% discount...this means u r actually paying 75%.....ur paying 75% of 60.
0.75 * 60 = $ 45...this is what u r paying....no need for subtracting
Answer:
Entries of I^k are are also identity elements.
Step-by-step explanation:
a) For the 2×2 identity matrix I, show that I² =I
![I^{2}=\left[\begin{array}{cc}1&0\\0&1\end{array}\right] \times \left[\begin{array}{cc}1&0\\0&1\end{array}\right] \\\\=\left[\begin{array}{cc}1\times 1+0\times 0&1\times 0+0\times 1\\0\times 1+1\times 0&0\times 0+1\times1\end{array}\right] \\\\=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=I%5E%7B2%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%5Ctimes%201%2B0%5Ctimes%200%261%5Ctimes%200%2B0%5Ctimes%201%5C%5C0%5Ctimes%201%2B1%5Ctimes%200%260%5Ctimes%200%2B1%5Ctimes1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Hence proved I² =I
b) For the n×n identity matrix I, show that I² =I
n×n identity matrix is as shown in figure
Elements of identity matrix are
As square of 1 is equal to 1 so for n×n identity matrix I, I² =I
(c) what do you think the enteries of Ik are?
As mentioned above
Any power of 1 is equal to 1 so kth power of 1 is also 1. According to this Ik=I
