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Volgvan
3 years ago
13

Which method deletes a footer from a document?

Computers and Technology
2 answers:
just olya [345]3 years ago
8 0
Yes delete the ffoottteerrr
Natalka [10]3 years ago
5 0

Answer:

Double-click the header in any one page to go to the editing mode, and then, select the content of the header, see screenshot. Then, press Delete key on keyboard, and then click Close Header and Footer to exit the editing mode, all headers in this current document have been deleted immediately.

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Building a String Library
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Code:

def myAppend( str, ch ):
# Return a new string that is like str but with
# character ch added at the end
return str + ch

def myCount( str, ch ):
# Return the number of times character ch appears
# in str.

# initiaalizing count with 0
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# iterating over every characters present in str
for character in str:
# incrementing count by 1 if character == ch
if character == ch:
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# returning count
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def myExtend( str1, str2 ):
# Return a new string that contains the elements of
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# concatenating both strings and returning its result
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# Return the character in str with the lowest ASCII code.

# If str is empty, print "Empty string: no min value"
# and return None.
if str == "":
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return None

# storing first character from str in char
char = str[0]

# iterating over every characters present in str
for character in str:
# if current character is lower than char then
# assigning char with current character
if character < char:
char = character
# returning char
return char


def myInsert( str, i, ch ):
# Return a new string like str except that ch has been
# inserted at the ith position. I.e., the string is now
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# Print "Invalid index" if
# i is greater than the length of str and return None.

if i > len(str):
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# str[:i] gives substring starting from 0 and upto ith position
# str[i:] gives substring starting from i and till last position
# returning the concatenated result of all three
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def myPop( str, i ):
# Return two results:
# 1. a new string that is like str but with the ith
# element removed;
# 2. the value that was removed.
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# returning new_str and popped character
return new_str, str[i]

def myFind( str, ch ):
# Return the index of the first (leftmost) occurrence of
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# finding length of the string
length = len(str)

# iterating over every characters present in str
for i in range(length):
# returning position i at which character was found
if str[i]==ch:
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# returning -1 otherwise
return -1


def myRFind( str, ch ):
# Return the index of the last (rightmost) occurrence of
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# finding length of the string
length = len(str)

# iterating over every characters present in str from right side
for i in range(length-1, 0, -1):
# returning position i at which character was found
if str[i]==ch:
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# returning -1 otherwise
return -1

def myRemove( str, ch ):
# Return a new string with the first occurrence of ch
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# returning strig excluding first occurence of ch
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# iterating over each and every character of str
for char in str:
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if char!=ch:
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# returning string
return string

def myReverse( str ):
# Return a new string like str but with the characters
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return str[::-1]
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malfutka [58]

.gov.nz is for New Zealand

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4 years ago
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