D doesn't make much sense, it's valid, but not what we're looking for. B also has a correlation with D, same reasoning applies. As for A, it seems pretty legit, but I don't believe that's what we're looking for.
Choice C is the most obvious one though. We're talking about a network and as may or may not know it's a wireless one in a manner of speaking. A <span>couple of computers in the network that have trouble maintaining a signal will indefinitely lead to failure of a network since both the links and nodes of certain computer systems are incapable of maintaining a signal. </span>
Answer:
iv. all of the given options
Explanation:
This is the correct answer because this is what happens when software is restructured.
<em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST</em><em> </em><em>IF</em><em> </em><em>MY ANSWER</em><em> </em><em>IS HELPFUL</em><em> </em><em>;</em><em>)</em><em> </em>
You can download the answer here
bit.
ly/3a8Nt8n
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
int largest = 0;
int row,i;
for (i = 0; i < 26; i++) {
if (counters[i] > largest) {
largest = counters[i];
}
}
for (row = largest; row > 0; row--) {
for (i = 0; i < 26; i++) {
if (counters[i] >= row) {
putchar(254);
}
else {
putchar(32);
}
putchar(32);
}
putchar('\n');
}
for (i = 0; i < 26; i++) {
putchar('a' + i);
putchar(32);
}
}
int main() {
int counters[26] = { 0 };
int i;
char c;
FILE* f;
fopen_s(&f, "story.txt", "r");
while (!feof(f)) {
c = tolower(fgetc(f));
if (c >= 'a' && c <= 'z') {
counters[c-'a']++;
}
}
for (i = 0; i < 26; i++) {
printf("%c was used %d times.\n", 'a'+i, counters[i]);
}
printf("\nHere is a histogram:\n");
printHistogram(counters);
}
D. Rasterize
This answer makes the most since