From your previous questions, you know
(3<em>w</em> + <em>w</em>⁴)' = 3 + 4<em>w</em>³
(2<em>w</em>² + 1)' = 4<em>w</em>
So by the quotient rule,
<em>R'(w)</em> = [ (2<em>w</em>² + 1)•(3<em>w</em> + <em>w</em>⁴)' - (3<em>w</em> + <em>w</em>⁴)•(2<em>w</em>² + 1)' ] / (2<em>w</em>² + 1)²
That is, the quotient rule gives
<em>R'(w)</em> = [ (denominator)•(derivative of numerator) - (numerator)•(derivative of denominator) ] / (denominator)²
I'm not entirely sure what is meant by "unsimplified". Technically, you could stop here. But since you already know the component derivatives, might as well put them to use:
<em>R'(w)</em> = [ (2<em>w</em>² + 1)•(3 + 4<em>w</em>³) - (3<em>w</em> + <em>w</em>⁴)•(4<em>w</em>) ] / (2<em>w</em>² + 1)²
B 5.75
Explaining:
5.25 - 1.75 = 3.5
3.5 - 9.25 = 5.75
4x^2 + x + 3 = 0
x = [-1 +/- sqrt (1^2 - 4 * 4 * 3)] / 8 = - 1 +/- sqrt ( --47) / 8
= ( - 1 +/- sqrt47i) / 8 = -0.125 + 0.857i , -0.125 - 0.857i
15x + 7y + 45x + 22y
= 60x + 29y
answer
A. 60x + 29y
Answer: Award a touch for X
Step-by-step explanation:
This is not a Mathematical question, it's a fencing question. It just requires the knowledge of the fencing sport.
Knowing the rules of the game, would let one know that fencer X landed the first legal touch on the valid surface of fencer Y.
Fencer Y's touch on Fencer X's valid surface arrives when fencer X already tripped while retreating and fell.
QED!
