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Write the quadratic equation in standard form: 5x2 + 3 = x
1 answer:
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Sin ø = opposite/hypotenuse = 2/3, cos ø = adjacent/hypotenuse = ?/3, tan ø = opposite/adjacent = 2/?, sec ø = 1/cos ø
to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2
Manipulating the equation to find the adjacent value = ?
adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)
so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>
to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2
Manipulating the equation to find the adjacent value = ?
adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)
so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>
Question:
What is the value of x? Enter your answer in the box. 68mm 57mm 129.2mm
The image of the triangle is attached below:
Answer:
The value of x is 98mm
Explanation:
It is given that VT = 57, TK = 129.2, YK = 68 and VK = x
Now, we need to find the value of x.
We shall determine the value of x, using angle bisector theorem,
Let us substitute the values, we get,
Switch sides, we have,
Multiply both sides by 57,
Simplifying, we get,
Adding both sides by 68, we have,
Thus, the value of x is 98mm
