Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
You lay out the triangle formula for area which would be A=(1/2)(b)(h)
plug in for variables
375=(1/2)(23.8)(b)
solve for b
You need to multiply 25 by 18 to find the total.
25 x 18 = 450.
There are 450 chocolate bars in the large box
The like terms: 5x^3 and x^3
Answer: 7.312
Step-by-step explanation: Hope this helped but you have to first divide 4/2 which makes 2, then 2/2 which is 1, 6/2 which makes 3, then 14/2 which makes 7
4/2= 2
2/2=1
6/2=3
14/2=7
7.312
