Simplify the 3v/h = s^2 so that s is isolated on one side of the equation.

1 answer:

7 0

Answer:Solve for h V=1/3pir^2h. V=13πr2h V = 1 3 π r 2 h. Since h h is on the right side of the equation, switch the sides so it is on the left side of the equation. 13⋅(πr2h)=V 1 3 ⋅ ( π r 2 h ) = V. Simplify the left side.

Step-by-step explanation:

Solve for h V=1/3pir^2h. V=13πr2h V = 1 3 π r 2 h. Since h h is on the right side of the equation, switch the sides so it is on the left side of the equation. 13⋅(πr2h)=V 1 3 ⋅ ( π r 2 h ) = V. Simplify the left side.

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Step-by-step explanation:

<u>Right Triangles</u>

Right triangles have one of its interior angles with a measure of 90°.

In right triangles the Pythagora's Theorem is satisfied.

Being c the longest side (hypotenuse), a and b the shorter sides (the legs), then:

$c^2=a^2+b^2$

We have modified the image to include some known data. Both triangles are congruent since they share one side, have a right angle, and have the same base length.

This means the value of x can be calculated as the hypotenuse of the triangle 3-6-x:

$x^2=3^2+6^2=9+36=45$