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vichka [17]
3 years ago
5

PLZ HELP ASAP The numbers of motor vehicle fatalities in the United States for the years 2010 and 2011 are listed in the table b

elow. Which conclusion is true based on the mean fatalities for the two years?
Month 2010 2011
January 2,290 2,365
February 2,016 2,912
March 2,423 3,011
April 2,777 2,638
May 2,934 2,459
June 2,795 2,154
July 3,095 2,268
August 3,083 2,750
September3,024 2,545
October 3,056 2,323
November 2,795 2,741
December 2,597 2,912

A.The variability in the monthly fatalities in 2011 is generally higher than in 2010.
B.The variability in the monthly fatalities in 2010 is equal to the variability in 2011.
C.The monthly fatalities in 2011 are generally higher than in 2010.
D.The monthly fatalities in 2010 are generally higher than in 2011.
E.The monthly fatalities in 2010 are approximately the same as in 2011.

Mathematics
1 answer:
Nonamiya [84]3 years ago
5 0
To find which measure of variability is greater and which average number of monthly fatalities is higher, you will need to calculate the mean and the mean absolute deviation for both years

The mean will tell us which is generally higher, and the mean absolute deviation will tell us which has a greater variability.

The correct answer is D.

Please see the attached picture for the work.

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Mumz [18]

The coordinates of vertex B' is P'(x,y) = (-2, -8).

<h3>How to calculate the coordinate of point by reflection</h3>

A point if reflected across the line y = -2 by means of the following formula:

P'(x,y) = P(x,y)+2\cdot [(x_{P}, -2)-P(x,y)] (1)

Where:

  • P(x,y) - Original point
  • x_{P} - x-Coordinate of point P
  • P'(x,y) - Resulting point

If we know that P(x,y) = (-2,4) and x_{P} = -2, then the coordinates of the vertex is:

P'(x,y) = (-2, 4) + 2\cdot [(-2,-2)-(-2,4)]

P'(x,y) = (-2, 4) +2\cdot (0, -6)

P'(x,y) = (-2, 4) + (0,-12)

P'(x,y) = (-2, -8)

The coordinates of vertex B' is P'(x,y) = (-2, -8). \blacksquare

To learn more on reflections, we kindly invite to check this verified question: brainly.com/question/1878272

3 0
3 years ago
Please help with these questions... I've been trying to figure them out for like twenty minutes and at this point I just don't h
vlada-n [284]

Answer:

1. y=2x^2-8X-1

2. y=-6x^2+36x-63

3. y=-3x^2+18x-34

4. y=9x^2+54x+76

5. y=-x^2+8x-22

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3 years ago
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krok68 [10]

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3 years ago
HELP ASAPPPP !!!! NEED ANSWERS NOW!!
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Answer: 1. 2nd endpoint  (24,-18)       2. 2nd endpoint: (-19,4)

Step-by-step explanation:

1.   \frac{-10+x}{2} = 7  x = 24

    \frac{6+y}{2} = -6    y= -18

2nd endpoint: (24,-18)

   

2.  \frac{-1+x}{2} = -10   x= -19  

   \frac{0+y}{2} =  2     y= 4

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3 years ago
Use the cut point method to find the solution set of the inequality x^3+3x^2-4x-12&gt;0.
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