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3 years ago

Which is the graph of a quadratic equation that has a negative discriminant?

Mathematics

1 answer:

luda_lava [24]3 years ago

5 0

Answer:

The first graph.

Step-by-step explanation:

When there is a negative discriminant, we call this "no solution" or "no real solution" because there are no x-intercepts. In the first graph, there are no x-intercepts.

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In one class the ratio of boys to girls is 5:6 if in this class it has 10 boys how much girls in this class

tigry1 [53]

Answer:

Step-by-step explanation:

5 : 6 = Number of boys to girls

(We have to ×2 to get from 5 to 10 so we must ×2 from 6 to 12)

10 : ? = Number of Boys to girls

10 : 12 = Number of Boys to girls

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3 years ago

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2 years ago

Which transformations will produce similar, but not congruent, figures?

n200080 [17]

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3 years ago

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What’s the answer to (16-x)2?

Oxana [17]

Answer:

-x + 18

Step-by-step explanation:

just add 16 and 2. this is the furthest it can be simplified

6 0

3 years ago

Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs

Roman55 [17]

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

$AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}$

$AB \approx 7.616$

$BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}$

$BC \approx 6.325$

$AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}$

$AC \approx 5.831$

Now we determine the area of the triangle by Heron's formula:

$A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)}$ (1)

$s = \frac{AB+BC + AC}{2}$ (2)

Where:

$A$ - Area of the triangle.

$s$ - Semiparameter.

If we know that $AB \approx 7.616$ , $BC \approx 6.325$ and $AC \approx 5.831$ , then the area of the triangle is:

$s \approx 9.886$

$A = 18$

The area of the triangle is 18 square units.

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2 years ago