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astraxan [27]
2 years ago
8

Help on this to please

Mathematics
2 answers:
Levart [38]2 years ago
7 0
<h2>Finding the slope of a line given the graph</h2><h3>Answer:</h3>

7) \frac{1}{2}\\

8) -\frac{5}{4}\\

<h3>Step-by-step explanation:</h3>

<em>Please refer to my Answer from this question to know more about the slope of a line: <u>brainly.com/question/24599351</u></em>

In graph 7, we can see that the points, (-1,-4) and (1, -3) are on the line so these can be our points 1 and 2. Now we can find the slope.

\frac{-3 -(-4)}{1-(-1)} \\ \frac{-3 +4}{1 +1} \\ \frac{1}{2}

The slope of line in graph 7 is \frac{1}{2}\\.

In graph 8, we can see that the points, (-4,4) and (0, -1) are on the line so these can be our points 1 and 2. Now we can find the slope.

\frac{-1 -4}{0-(-4)} \\ \frac{-1 -4}{0 +4} \\ \frac{-5}{4} \\ -\frac{5}{4}

The slope of line in graph 8 is -\frac{5}{4}\\.

d1i1m1o1n [39]2 years ago
5 0

Answer:

7). up 4 over  4

8). up 1 over 2

Step-by-step explanation:

hope this helps :)

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Together Juan and Maria can clean the house in 6 hours. Alone Juan can complete the job 2 hours faster than Maria. Find to the n
MaRussiya [10]

Answer:

the correct answer is 50 really hope this helped :)

Step-by-step explanation:

8 0
2 years ago
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
Use the distributive property to create an equivalent expression to 7(2j + 3 + 2j).
Scorpion4ik [409]

Answer:

28j + 21

Step-by-step explanation:

combine like terms

7(2j+ 3+ 2j)

7(4j+3)

Distribute

7(4j + 3)

=

28j + 21

6 0
2 years ago
Read 2 more answers
Simplify. Please show work
GuDViN [60]

Answer:

\frac{4b^5}{c^3}

Step-by-step explanation:

\frac{36b^4c^2}{9b^{-1}c^5}

\frac{36b^4c^2}{9b^{-1}c^5}\\\\\frac{4b^{4+1}}{c^{5-2}}\\\\\frac{4b^5}{c^3}

Hope this helps!

5 0
2 years ago
Cameron ran 3.8 miles per every 1.9 miles that Samantha ran and if Samantha and 7.6 miles how far did Cameron run
bija089 [108]
3.8 / 1.9 = x / 7.6....3,8 miles to 1.9 miles = x miles to 7.6 miles
cross multiply
(1.9)(x) = (3.8)(7.6)
1.9x = 28.88
x = 28.88 / 1.9
x = 15.2 <== Cameron ran 15.2 miles
8 0
3 years ago
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