So what you do is see all the denomenators and factor them (denomenaotrs are the bottom numbres)
10,4,10,25
10=2 times 5
4=2 times 2
10=2 times 5
25=5 times 5
we need to include all of them so we need at leas two 2's, and two 5's
2 times 2 times 5 times 5=100
leact common denomator is 100
(+8)+(-9)
the answer is -1
Answer:
The other dimension of the pasture (width) is 
Step-by-step explanation:
In this problem I assume that the pasture has the shape of a rectangle.
Let
x -----> the length of the pasture
y -----> the width of the pasture
we know that
The area of the pasture (rectangle) is equal to

we have


substitute and solve for y



We need to see the graph in order to answer
11
125
85
------
210
2
---------
420
3
--------
$12.50