<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
x = -1
Step-by-step explanation:


or

Since both sides have the same base, we can write
10x = 5x - 5
or
5x = -5
x = -1
It means that the variables cancelled out and you might have made an error in your working, or it could also mean that that solution was not going to work out (hence leading 0=0). It all depends on the question.
Hope I helped :)
Answer:
The sum of the numbers in each circle is 17
Step-by-step explanation:
The numbers to choose from are:
2, 3, 5, 7
By this alone the biggest number must be in the overlap of the three circles.
Then just fill in the numbers in such a way that they all are used.
The sum of the numbers in each circle is 17.
See picture for a solution.
Answer:
it sin 60
Step-by-step explanation: