Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 244 meters

1 answer:

6 0

We know that

[perimeter of rectangle]=2*(length+width)

Let
x-----------> length
y-----------> width
so
P=2*(x+y)-----------> 244=2*(x+y)-----> x+y=122-------> y=122-x

Area=x*y-------> x*(122-x)----> 122x-x²

find the derivative function and equals to zero

122-2x=0-----> 122=2x----------> x=61 m
y=122-x------> y=122-61---------> y=61 m

the maximum area is given by a square

the answer is
is a square of side 61 m

You might be interested in

What is m∠AEB? Enter your answer in the box.

avanturin [10]

Angle AEB and angle CED are vertical angles, this means they equal each other, therefore we set their values as an equation and solve:

5x-10=3x+40
Subtract 3x to both sides
2x-10=40
Add 10 to both sides
2x=50
Divide both sides by 2
x=25

After we have gotten the value of x we can plug it in into the equation of angle AEB:

5x-10
Substitute x by 25
5(25)-10
Distribute
125-10
Substract
115

The measurement of angle AEB is 115

Hope it helped!, have a great day.

7 0

3 years ago

What is 2 times 2 and 7/8

anyanavicka [17]

2 x 2 7/8 = 5 3/4 hope it helps

6 0

3 years ago

Read 2 more answers

Can someone help me please? I don't understand this at all

Margarita [4]

X Is a number so ( x +12) a

6 0