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nikklg [1K]
3 years ago
9

If pis inversely proportional to the square of q, and p is 23 when q is 4, determine p

Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0

Answer:

p\ =\ 92

Step-by-step explanation:

Given

p\ \alpha\ \frac{1}{q^2}

p =23; q=4

Required

Find p, when q = 2

We have:

p\ \alpha\ \frac{1}{q^2}

Express as equation

p\ =\ \frac{k}{q^2}

Make k the subject

k =pq^2

When: p =23; q=4

k =23 * 4^2

k =368

When q = 2, we have:

p\ =\ \frac{k}{q^2}

p\ =\ \frac{368}{2^2}

p\ =\ \frac{368}{4}

p\ =\ 92

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Answer:

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Step-by-step explanation:

One of the angles is 90 degrees.

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2 years ago
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Sarah is a computer engineer and manager and works for a software company. She receives a
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Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = a

Given that:

a_4=129\\a_{10}=207

Formula for n^{th} term of an Arithmetic Progression is given as:

a_n=a+(n-1)d

Where d will represent the number of projects increased every year.

and n is the year number.

a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)

Subtracting (2) from (1):

78 = 6d\\\Rightarrow d =13

By equation (1):

129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90

<em>Number of projects in the first year = 90</em>

<em></em>

<em>b) </em>

Number of projects in the twelfth year =

a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233

Each project pays $500

Earnings in the twelfth year = 233 \times 500 = $116500

Sum of an AP is given as:

S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938

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astra-53 [7]

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Step-by-step explanation:

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2 years ago
Based on historical data, your manager believes that 26% of the company's orders come from first-time customers. A random sample
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Answer:

\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})

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And if we find the parameters we got:

\mu_p = 0.26

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And we can find this probability:

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And if we use the normal standard table or excel we got:

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Step-by-step explanation:

For this case we have the following info given:

p = 0.26 represent the proportion of the company's orders come from first-time customers

n=158 represent the sample size

And we want to find the following probability:

p(\hat p >0.4)

And we can use the normal approximation since we have the following two conditions:

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And for this case the distribution for the sample proportion is given by:

\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})

And we can use the z score formula given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

And if we find the parameters we got:

\mu_p = 0.26

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And we can find the z score for the value of 0.4 and we got:

z = \frac{0.4-0.26}{0.0349}= 4.0119

And we can find this probability:

P(z>4.0119) = 1-P(z

And if we use the normal standard table or excel we got:

P(z>4.0119) = 1-P(z

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2 years ago
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