The time required to transmit the frame and receive the acknowledgment DIFS + 3SIFS +820μsec
<h3>
What is Bytes?</h3>
- Digital information is stored in units called bytes, which typically have eight bits.
- The byte is the lowest addressable unit of memory in various computer architectures because it was historically the amount of bits needed to encode a single character of text in a computer.
- Network protocol specifications such as The Internet Protocol (RFC 791) refer to an 8-bit byte as an octet to distinguish them from the ordinary 8-bit definition.
- Depending on the bit endianness, an octet's bits are typically counted from 0 to 7 or 7 to 0, respectively. Since the initial bit is a zero, the eighth bit is a seven.
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I hope you are trying to ask the question below:
<u>Question</u>:
Suppose an 802.11 b station is configured to always reserve the channel with the RTS/CTS sequence.
Suppose this station suddenly wants to transmit 1,000 bytes of data, and all other stations are idle at this time.
As a function of SIFS and DIFS, and ignoring propagation delay and assuming no bit errors, calculate the time required to transmit the frame and receive the acknowledgment.
Answer:
The Producer
Explanation:
In a market economy, the maker will choose what to create, the amount to deliver, what to charge clients for those products, and what to pay workers. These choices in an unregulated economy are impacted by the tensions of contest, supply, and request.
BRAINLIEST?
Answer:
3,579 units
Explanation:
Computation of the given data are as follows:
Contribution Margin = Selling price - Variable expense
= $235 - $99 = $136
So, to achieve target profit of $34,000
Target Contribution margin = Fixed expense + Target profit
= $452,740 + $34,000
= $486,740
So, sales unit = Target contribution margin ÷ Contribution margin
= $486,740 ÷ $136
= 3,578.97 or 3,579 units
Max has 250$ because the case for a iPad is at least 20$
