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Darina [25.2K]
3 years ago
5

Drag the values into the boxes to classify each number as rational or irrational.

Mathematics
1 answer:
ycow [4]3 years ago
7 0
The ones with ✓ signs are irrational the rest are rational. note this is not generally true but it is for this particular set
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Cramers rule<br>hurry up plzzz​
olya-2409 [2.1K]

Answer:

Answers provided below

Step-by-step explanation:

From the simultaneous linear equation, we have the coefficient matrix as;

(3 4 5)

(2 -1 8)

(5 -2 7)

The x-matrix is Dx is given by;

(18 4 5)

(13 -1 8)

(20 -2 7)

Similarly, the y-matrix Dy is given by;

(3 18 5)

(2 13 8)

(5 -20 7)

Also,the z-matrix Dz is given by;

(3 4 18)

(2 -1 13)

(5 -2 -20)

Determinant of the coefficient matrix from online determinant calculator is;

D = 136

Determinant of the x-matrix from online determinant calculator is; Dx = 92

Determinant of the y-matrix from online determinant calculator is; Dy = 696

Determinant of the z-matrix from online determinant calculator is; Dz = 576

From crammers rule;

x = Dx/D = 92/136

y = Dy/D = 696/136

z = Dz/D = 576/136

6 0
2 years ago
Simplify these expressions
Xelga [282]
\frac{10a}{2} \\ \\ 5a \\ \\

The answer is: 5a

-----------

\frac{36b}{6b} \\ \\  \frac{36}{6} \\ \\ 6 \\ \\

The answer is: 6

------------

\frac{16c^2}{8c} \\ \\ 2c^{2-1} \\ \\ 2c^1 \\ \\ 2c \\ \\

The answer is: 2c

------------

\frac{18ab^2}{2b} \\ \\ 9ab^{2-1} \\ \\ 9ab^1 \\ \\ 9ab \\ \\

The answer is: 9ab

------------

\frac{40b^2c^2}{5bc} \\ \\ 8b^{2-1} c^{2-1} \\ \\ 8b^1c^1 \\ \\ 8bc^1 \\ \\ 8bc \\ \\

The answer is: 8bc

-----------

\frac{63ab^2c^3}{7b^2c^2} \\ \\  \frac{63ac^3}{7c^2} \\ \\ 9ac^{3-2} \\ \\ 9ac^1 \\ \\ 9ac \\ \\

The answer is: 9ac
6 0
3 years ago
Midpoint of (1,3) and (4,-5)
crimeas [40]

Answer:

The rigth answer is, ( 5/2 , -1 )

Step-by-step explanation:

To find the midpoint we use the respective formula:

m = ( x1 + x2 / 2 ,  y1 + y2 / 2 )

We replace:

m = ( 1 + 4/2  ,  3 + (- 5) / 2 )

We solve:

m = ( 5/2 ,  -1 )

5 0
2 years ago
Ty flipped a coin and counted how many times it landed on heads and how many times it landed on
lesya [120]
<h3>Answer:  13/28</h3>

========================================================

Reason:

The table shows he got 26 heads out of 26+30 = 56 coin flips.

26/56 = (2*13)/(2*28) = 13/28 is the empirical or experimetnal probablity of getting heads.

Side note: 13/28 = 0.4643 = 46.43% approximately which is fairly close to 50%

6 0
2 years ago
......................................
Julli [10]
Lol hiiiiiiiiiiiiiiiiii
7 0
2 years ago
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