Please help with number 5. Select all that apply.
1 answer:
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The perimeter of a rectangle is calculated as
Perimeter= 2(length + breadth )
So, Perimeter = 2*length + 2*breadth
Now we are given the length as 34.2 meters and breadth as 27.8 meters
So the perimeter will be
2(34.2+27.8) meters
which equals 2(62) meters
Hence Perimeter = 124 meters
The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)
----------------(from equation 1)
----------------(given p=58 inches)
----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.
as, -----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.