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3 years ago

9

In order to test a hypothesis, the variable that the scientist changes to a predetermined value is known as _________________. i

s. the controlled variable
b. the dependent variable

c. the independent variable

d. all of the above

1 answer:

eimsori [14]3 years ago

8 0

The controlled variable

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Identify each function as a constant, direct variation, absolute value, or greatest integer function.

Anton [14]

None of those describe this function.

It's not a constant function, because it is not equal to a constant (something that isn't a variable)

It doesn't show direct variation, because it can't be represented in the form
y = kx.

It isn't an absolute value function because the absolute value isn't taken anywhere.
If it was an absolute value function it would look something like this:
$g(x) = |x+3|$

It isn't a greatest integer function, because the greatest integer isn't taken anywhere.
If it was a greatest integer function it would look something like this:
$g(x) = \left \lfloor{x + 3}\right \rfloor$

Are you sure you typed that question right?

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3 years ago

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stealth61 [152]

Answer:

AAA

Step-by-step explanation:

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2 years ago

I need help on 11, 12 and 13 please ... :(

Lynna [10]

Question 11= B
Question 13= C
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3 years ago

sara received 73 votes in the school election. Ben received 25 votes fewer than Sara. How many students Voted?

Anna007 [38]

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3 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

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2 years ago