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Alexandra [31]
3 years ago
6

After placing the compass' point on one end of the line segment and striking an arc above and below that segment, what is the ne

xt step in constructing a perpendicular bisector?
A) Draw an arc above and below the line.
B) Draw an arc on both ends of the line segment.
C) Place the compass' point on the other end of the segment.
D) Set the compass' width to approximately 1/2 the length of the segment.
Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

D. Set the compass' width to approximately \frac{2}{3} the length of the segment.

Step-by-step explanation:

The compass must be extended before continuing with the next step.

S_A_V [24]3 years ago
4 0
Ill say, C) Place the compass' point on the other end of the segment.
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5-2(4a+1)+3a=13 <br><br> A= 2/3<br> A= -2<br> A= -6/5<br> A=2
VMariaS [17]

Answer:

                   a = -2

Simplifying 5 + -2(4a + 1) + 3a = 13 Reorder the terms: 5 + -2(1 + 4a) + 3a = 13 5 + (1 * -2 + 4a * -2) + 3a = 13 5 + (-2 + -8a) + 3a = 13 Combine like terms: 5 + -2 = 3 3 + -8a + 3a = 13 Combine like terms: -8a + 3a = -5a 3 + -5a = 13 Solving 3 + -5a = 13 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5a = 13 + -3 Combine like terms: 3 + -3 = 0 0 + -5a = 13 + -3 -5a = 13 + -3 Combine like terms: 13 + -3 = 10 -5a = 10 Divide each side by '-5'. a = -2

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3 years ago
A storage bin in the shape of a rectangular prism has a volume of 10x3+9x2+2x.What linear expressions can represent possible dim
Mice21 [21]

Answer:72

Step-by-step explanation:

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3 years ago
A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded
Crank

Answer:

A=81(\pi-1)\ in^2

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

A=\pi r^{2}

we have

r=18/2=9\ in ---> the radius is half the diameter

substitute

A=\pi (9)^{2}\\A=81\pi\ in^2

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

D^2=2b^2

where

b is the length side of the square

we have

D=18\ in

substitute

18^2=2b^2

solve for b^2

b^2=162\ in^2 -----> is the area of the square

Divide by 2

162/2=81\ in^2

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The  area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

A=(81\pi-81)\ in^2

simplify

A=81(\pi-1)\ in^2

8 0
3 years ago
Running out of time! Please help and show work! Thank you! Will mark brainliest!
VikaD [51]
<h3>​(-3j²k³)²(2j²k)³</h3>

(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.​</em>

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= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹​

​Answer = 72j¹⁰k⁹

​Hope this helps!​​​​

​​\textit{\textbf{Spymore}}​​​​​​

5 0
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Matthew changes $770 into rupees. He receives 40 000 rupees.
Yanka [14]

Answer:

About 51.94 rupees (rounded).

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