You can divide the figure as follows:
- A vertical rectangle, 5 meters tall and 2 meters wide, on the top right.
- A horizontal rectangle, 2 meters tall and 5 meters wide, on the bottom left
- A 2x2 meters square on the bottom right, where the two rectangles meet.
The area of the rectangles is 5x2=10 meters squared, while the area of the square is 2x2=4 meters squared.
So, the total area is 10+4=14 meters squared.
Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =

- 2 1/4 (mix fraction)
- 9/4 (improper fraction)
Divide the 114 by 6t to get an anwer
Answer:
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