Answer:

Step-by-step explanation:
The vertex form of an equation of a parabola:

(h, k) - vertex
We have

We must use the formula: 

Use the distributive formula a(b + c) = ab + ac

Answer:
no, it’s not correct
Step-by-step explanation:
I just know, it would be the second one
24,48,72,96,120,144,168,192,216,240,264...360
90,180,270,360
LCM of 24 and 90 is 360
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hope it helps
Answer:
50
Step-by-step explanation:
Each question is 6%/3 = 2% worth. If each question is worth 2% then total questions must be 50 (cuz that would be 2% x 50 (total question) = 100%).
It's the same only adding a zero at the end