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ollegr [7]
3 years ago
6

You haft too use elimination to solve this thank you

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

x=0, y=-2

Step-by-step explanation:

Because 9y appears twice in both equations, you can subtract the equations to eliminate the y variable so you can solve for x:

-7x + 9y = -18

-(4x + 9y = -18)

__________

-11x = 0

x = 0

Since we know x=0, then we plug it back into one of the equations to get the value of y:

-7x + 9y = -18

-7(0) + 9y = -18

0 + 9y = -18

9y = -18

y = -2

Therefore, x=0, and y=-2

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20 Points- Which of the following is true for f of x equals the quotient of the quantity x squared plus 9 and the quantity x min
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Answer:

There is a non-removable discontinuity at x = 3

Step-by-step explanation:

We are  given that

f(x)=\frac{x^2+9}{x-3}

We have to find true statement about given function.

\lim_{x\rightarrow 3}f(x)=\lim_{x\rightarrow 3}\frac{x^2+9}{x-3}

=\infty

It is not removable discontinuity.

x-3=0

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The function f(x) is not define at x=3. Therefore, the function f(x) is continuous for all real numbers except x=3.

Therefore, x=3 is non- removable discontinuity of function f(x).

Hence, option B is correct.

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3 years ago
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4 years ago
A teacher has 7 candy bars to equally share with 8 students. How many candy bars does each student receive?
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2 years ago
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Simplify the expression. Explain each step 2 + (5 + y)
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Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the re
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Answer:

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Area is symmetric so will be twice the integral from zero to 1

( I cannot seem to figure out how to make the lower limit negative in this editor)

A = 2\int\limits^1_0 {(x^2 + 3) - 4x^2} \, dx)

A = 2\int\limits^1_0 {-3x^2 + 3} \, dx

A = 6\int\limits^1_0 {-x^2 + 1} \, dx

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