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antoniya [11.8K]
3 years ago
14

A cylindrical container of height 28cm and diameter 18cm is filled with water.The water is then poured into another container wi

th a rectangular Base of length 27cm and width 11cm.Calculate the depth of the water in the container [Take π=22÷7]​
Mathematics
2 answers:
sergey [27]3 years ago
5 0

Answer:

qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq

Step-by-step explanation:

Harman [31]3 years ago
4 0

Answer:

answr

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Surface Areas and Volumes

Surface Area of Right Circular Cylinders and Cones

A cylindrical container wit...

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Asked on December 20, 2019 by

Ziya Vïvəķ

A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

2

56

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

2

h=32×22×14 cm

3

7

22

×(28)

2

×h=9856 cm

h=

22×784

9856×7

cm

h=4 cm

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