Digit, number, WHOLE NUMBER
Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
Answer:
145
Step-by-step explanation:
six can go into eight once with a remainder of two, next you bring down the seven and you will get twenty seven, six can go into twenty seven four times six by four is 24,27 take away 24 is 3 then you bring down the one, six can go into 31 five times, six by five is 30, 31 take away 30 is one