Is 2x/3 the same as (2/3)x ? Just wondering

2 answers:

6 0

the best way to understand is putting a number in place of x and seeing if they are equal to eachother so just to make it simple i'll make x=6

so your first equation is 2(6)/3 =12/3=4 now the other equation would be (2/3)6 = 6

i actually solved it putting 2 in place of x and got the same answer for both so i think they're the same

lina2011 [118]3 years ago

6 0

Honestly i dont think so because in 2x/3 its 2 times x divided by 3 while in the other problem you divide 2/3 then multiply the answer by x! So even though that may work sometimes always double check!!!

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2 years ago

12n^3 + 16n^3 can someone please help me with this?

vodka [1.7K]

Answer:

$4n^{3} (3n^{2} + 4)$

Step-by-step explanation:

Assuming the problem is asking you to factor out the formula, it can be done easily by finding a common number with the two givens.

4 goes into both 12 and 16 evenly, so we will use this to factor. But that's not all, we have the n-variable to worry about.

Look at the n-variable exponents in the problem, take the highest power that can go be subtracted from both and use that. We have a $n^{5}$ and $n^{3}$ . Since 5 can't go into 3, we must use 3 to factor.

Our factoring variable will therefore be $4n^{3}$ . Now, use this to simply divide and get the answer:

$( 12n^{5} + 16n^{3} ) / 4n^{3} = 4n^{3}(3n^{2} + 4)$

So how did we get this? For the whole numbers, we have to divide: (12/4, 16/4). Next, we have to minus the exponents since we are dividing.

When dividing the 12 and 4, minus the $n^{5}$ and $n^{3}$ to get $n^{2}$ . Get rid of the $n^{3}$ term for the 16 and leave the 4. And there's your answer!