Given that the first spinner has three equal sectors labelled 1, 2 and 3; and the second spinner has equal sectors labelled 3, 4, 5 and 6.
The number of possible outcomes that do not show a 1 on the first spinner is 2 (i.e. the first spinner shows 2 or 3).
The number of possible outcomes that the second spinner show the number 4 is 1 (i.e. the second spinner shows 4)
In probability, the word 'and' goes with multiplication.
Therefore, <span>the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner</span> is given by 2 x 1 = 2 possible outcomes.
i.e. the first spinner shows the number 2 and the second spinner shows the number 4 or the first spinner shows the number 3 and the second spinner shows the number 4.
Answer:
c
Step-by-step explanation:
to convert a fraction to a decimal, like say a/b is really simply the quotient of a ÷ b.
now, let's first convert the mixed fraction to improper, and then do the division.
![\bf \stackrel{mixed}{5\frac{5}{16}}\implies \cfrac{5\cdot 16+5}{16}\implies \stackrel{improper}{\cfrac{85}{16}}\\\\[-0.35em] \rule{31em}{0.25pt}\\\\ \cfrac{85}{16}\implies 85\div 16\implies 5.3125](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B5%7D%7B16%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%2016%2B5%7D%7B16%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B85%7D%7B16%7D%7D%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B31em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ccfrac%7B85%7D%7B16%7D%5Cimplies%2085%5Cdiv%2016%5Cimplies%205.3125%20)
