Find the vertex for the parabola given by the function ƒ(x) = −3x2 − 6x.
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<h3>Given :-</h3>
- Perimeter of triangle = 42
- Side 1 of triangle = (x + 4)
- Side 2 of triangle = (3x + 8)
- Side 3 of triangle = (5x + 6)
- Length of sides
So to find length of sides we have to find the value of x.We can find value of x , by this formula:
So:-
- Side 1 of triangle = (x + 4)
- Side 1 of triangle =2.67 + 4
- Side 1 of triangle = 6.67
- Side 2 of triangle = 3x + 8
- Side 2 of triangle = 3 × 6.67 + 8
- Side 2 of triangle = 20.01 + 8
- Side 2 of triangle = 28.01
- Side 3 of triangle = 5x + 6
- Side 3 of triangle = 5 × 2.67 + 6
- Side 3 of triangle = 13.35 + 6
- Side 3 of triangle = 19.35
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~WindyMint
+
= 34
The equation of a circle in standard form is
+
=
where (a , b) are the coordinates of the centre and r is the radius
The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints
Using the midpoint formula
midpoint = [(x
+
,
(
+
where (,
=(3,8) and (
,
=(-7,2)
centre = ((3-7),
(8+2)) = (-2,5)
Calculate r using the distance formula
r = √(-
)²+(
-
)²)
= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34
equation of circle is : (x+2)²+(y-5)² = 34