True.
If the clock loses 1 second every hour that passes then after 4 hours it will be 4 seconds off, 5 hours will be 5 seconds off, etc. It would continue and turn into minutes and hours off.
I do not know what to answer here can you repost this question and make it a little bit more clear as i am sure it is really confusing to everybody else as it stands right now<span />
Answer:
543
Step-by-step explanation:
Lim as x approches 0 of (e^(5x) - 1 - 5x)/x^2 = lim as x approaches 0 of (5e^(5x) - 5)/2x = lim as x approaches 0 of 25e^(5x)/2 = 25/2 = 12.5
Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.
Num days late = 0.8 * 30=24
So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
