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Fynjy0 [20]
3 years ago
14

9.

Mathematics
1 answer:
Sloan [31]3 years ago
5 0

Answer:

your answer is 1

Step-by-step explanation:

when you work with negative numbers, you have to work backwards.

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Jenny bought 4 DVD's for $25.20. What was the unit rate?
alukav5142 [94]

I think its 6.3........

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3 years ago
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A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's
STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

3 0
3 years ago
A point that varies greatly from all other data points
Tju [1.3M]

Answer:

Outlier

Step-by-step explanation:

Very simple. No explanation.

8 0
3 years ago
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10 x 1/2+(-6)(-3) simplified in steps
miv72 [106K]

Answer:

23

Step-by-step explanation:

Remember PEMDAS/order of operations (Parentheses, exponent, multiplication, division, addition, subtraction)

10*1/2+(-6)(-3)

10*1/2+18

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23

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3 years ago
How to find if it is a function or not:
Leto [7]

Answer: It is not a function.

Step-by-step explanation:

A function is something that "eats" an input and transforms it into an output.

We write them as y = f(x)

Where x is the input, and y is the output.

Now, a function has an important rule, for each input x, the function can only "transform it" (or map it) into only one possible output.

This means that, for example, if we have, for x = x1.

And a single

f(x1) = y1

f(x1) = y2

where y1 and y2 are different values.

Then this is not a function, because it is mapping the value x1 into two different outputs.

In this case, we would have:

f(Z) = A.

So Z is the input, but we know that a ZIP code works for an entire city, and in a given city we have lots of different street addresses, then for a single value of the input, Z, we have a lot of possible values of the output.

This means taht the set (Z, A) can not represent a function.

6 0
3 years ago
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