Answer:
a_{n} = a_{1} + (n-1)d
a_n = the nᵗʰ term in the sequence
a_1 = the first term in the sequence
d = the common difference between terms
The general term of an arithmetic sequence can be written in terms of its first term a1, common difference d, and index n as follows: an=a1+(n−1)d. ... The nth partial sum of an arithmetic sequence can be calculated using the first and last terms as follows: Sn=n(a1+an)2.
5^2 + 3^2 (equals to 34) ; That's the wrong expression
It should look like this : (5+3)^2 (which equals to 64)
Answer: 0.4987
Step-by-step explanation:
Given : The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with
Mean : 
Standard deviation : 
Let X be the random variable that represents the weight of randomly selected student .
Z score : 
For x = 5 lbs

For x = 11 lbs

By using the standard normal distribution table , the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs :-

Hence, the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs =0.4987
Answer:
Tristan has a 17/24 lb fraction of a pound of grapes now.
Step-by-step explanation:
Given
- The number of grapes Tristan had at home = 1/3 lb
- The number of grapes Tristan had at the store = 3/8 lb
To determine
What fraction of a pound of grapes does Tristan have now?
In order to get the total fraction of a pound of grapes, all we need is to add the number of grapes Tristan had at home and the number of grapes Tristan had at the store.
i.e.
Current number grapes = 1/3 + 3/8
Least Common Multiple of 3, 8: 24
Adjust fractions based on L.C.M
= 8/24 + 9/24
Apply the fraction rule: 
= (8 + 9) / 24
= 17/24 lb
Therefore, Tristan has a 17/24 lb fraction of a pound of grapes now.