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2 years ago

What is 8n-(2n-3)=12 ?

1 answer:

5 0

Okay luv so let's solve this equation together:
8n-(2n-3)=12
simplify
8n+-1(2n-3)=12
8n+-1(2n)+(-1)(-3)=12
8n+-2n+3=12
(8n+-2n)+(3)=12 Combine like terms
6n+3=12
Then subtract from both sides
6n+3-3=12-3
6n=9
Then divide both sides by 6
6n/6=9/6
so...n=3/2

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Part E<br> 1e. Subtract the binomial 12y2 – 4y3 from the trinomial 7y - 2y3 + 5y2

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Answer:

2y^3-7y^2+7y

Step-by-step explanation:

7y - 2y^3 + 5y^2 - ( 12y^2 – 4y^3)

Distribute the minus sign

7y - 2y^3 + 5y^2 - 12y^2 + 4y^3

Combine like terms

2y^3-7y^2+7y

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2 years ago

If mn = 16 and m^2 + n^2 = 68 then (m+n)^2 =

Dima020 [189]

Answer:

B. 100

Step-by-step explanation:

(m + n)^2

= m^2 + 2mn + n^2

Rearrange

(m^2 + n^2) + 2mn

Substitute

(68) + 2*16

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= 100

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2 years ago

The Roman numeral which represents the number in standard form for 3,089 is?

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MMMLXXXIX

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2 years ago

Dale is standing 2x+7 feet from the base of a tower, the tower is 8x-4 feet tall. What is the distance between dale and the top

V125BC [204]

Answer:

6x - 11 feet

Step-by-step explanation:

Dale is standing (2x + 7) feet height from the base of the tower.

And the tower is given to be (8x - 4)feet tall.

We have to find the distance between Dale and the top of the tower.

Now, the distance between dale and the top of the tower = height of the tower - height of Dale = (8x - 4) - (2x + 7) = (6x - 11) feet. (Answer)

4 0

2 years ago

Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none

Marysya12 [62]

Answer: The required solution of the given system is

(x, y) = (3, 1) and (4, 0).

Step-by-step explanation: We are given to solve the following system of equations :

$x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (i), we have

$x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of y from equation (iii) in equation (ii), we get

$y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.$

When, x = 3, then from (iii), we get

$y=4-3=1.$

And, when x = 4, then from (iii), we get

$y=4-4=0.$

Thus, the required solution of the given system is

(x, y) = (3, 1) and (4, 0).

8 0

2 years ago