Go one box left from the 0 an 3 down
Differentiate:x^2 + y^2 = 4
You get this:2x + 2yy' = 0
bring the x variable on the other side:2yy' = -2x
Now divide 2y to leave y' by itself:y' = -2x/2y
Answer: y' = -x/y
The given relation is not a implicit solution to the given differential equation.
Answer:
4322
Step-by-step explanation:
1/8 of the cake has not been eaten.
