Question

If you are pushing on a box with a force of 20 N and there is a force of 7 N on the box due to sliding friction, what is the net force on the box? I need the answer ASAP!

Answer 1

I think you would do 20+7 = 27N as the net force

Answer 2

Answer:

Net force acting on the box, $F_{net}=13\ N$

Explanation:

It is given that,

Force with which the box is pushed, F = 20 N

Force acting due to sliding friction, f = 7 N

Sliding friction is a type of resistive force. It always opposes the motion of an object. Here, the force of 7 N will act in the opposite direction of motion. As a result, the net force acting on the box is given by :

$F_{net}=F-f$

$F_{net}=20-7$

$F_{net}=13\ N$

So, the net force acting on the box is 13 N. Hence, this is the required solution.