If you are pushing on a box with a force of 20 N and there is a force of 7 N on the box due to sliding friction, what is the net
2 answers:
Answer:
Net force acting on the box,
Explanation:
It is given that,
Force with which the box is pushed, F = 20 N
Force acting due to sliding friction, f = 7 N
Sliding friction is a type of resistive force. It always opposes the motion of an object. Here, the force of 7 N will act in the opposite direction of motion. As a result, the net force acting on the box is given by :
So, the net force acting on the box is 13 N. Hence, this is the required solution.
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Answer:
The y-axis should be labelled as W in Newtons (kg·m/s²)
Explanation:
The given data is presented here as follows;
Mass (kg) Newtons (kg·m/s²)
3.2 31.381
4.6 45.1111
6.1 59.821
7.4 72.569
9 89.241
10.4 101.989
10.9 106.892
From the table, it can be seen that there is a nearly linear relationship between the amount of Newtons and the mass, as the slope of the data has a relatively constant slope
Therefore, the data can be said to be a function of Weight in Newtons to the mass in kilograms such that the weight depends on the mass as follows;
W(m) in Newtons = Mass, m in kg × g
Where;
g is the constant of proportionality
Therefore, the y-axis component which is the dependent variable is the function, W(m) = Weight of the body while the x-axis component which is the independent variable is the mass. m
The graph of the data is created with Microsoft Excel give the slope which is the constant of proportionality, g = 9.8379, which is the acceleration due to gravity g ≈ 9.8 m/s²
We therefore label the y-axis as W in Newtons (kg·m/s²)
