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erica [24]
3 years ago
6

Manipulate p+x=r to solve for x

Physics
2 answers:
kotykmax [81]3 years ago
6 0
P+x=r
-p     -p
Answer: x=r-p

Hope this helps.
Tanzania [10]3 years ago
4 0
X=r-p. Maybe I don't understand, but I am assuming that you need to isolate for X? you simply subtract p from both sides.<span />
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a measure has true value of 2.00and the measurement value was found to e 1.95.calculate the precision of the measuring instrumen
DiKsa [7]

The precision of the measuring instruments will be 2.5%.

<h3>What is precision?</h3>

It should be noted that precision simply means how close a test result will be when it's repeated.

In this case, the precision of the measuring instruments will be:

= (2 - 1.95)/2.

= 0.05/2

= 2.5%

Therefore, the the precision of the measuring instruments will be 2.5%.

Learn more about precision on:

brainly.com/question/5792909

8 0
2 years ago
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20 points ! Help!!! Please and thank you !
Delvig [45]

Number 7is 64. 8 is 486 because 3 to the 5th is 243 then multiply by 2.

9 is 1003.092

10. Is 5

4 0
4 years ago
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What makes air pollution a global problem?<br> A Wind <br> B Travel<br> C Gravity<br> D Sunlight
snow_tiger [21]
The answer is D 
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8 0
3 years ago
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A charged box (m=445 g, ????=+2.50 μC) is placed on a frictionless incline plane. Another charged box (????=+75.0 μC) is fixed i
victus00 [196]

The concept required to perform this exercise is given by the coulomb law.

The force expressed according to this law is given by

F= \frac{kqQ}{r^2}

Where,

k = 8.99 * 10^9 N m^2 / C^2.

q = charges of the objects

r= distance/radius

Our values are previously given, so

q= 2.5*10^{-6}C\\Q= 75*10^{-6}C\\r=0.59

Replacing,

F=\frac{kqQ}{r^2}

F= \frac{(8.99 x 10^9)(2.5*10^{-6})(75*10^{-6})}{0.59^2}

F= 4.8423N

The force acting on the block are given by,

F-mgsin\theta = ma

a = \frac{F-mgsin\theta}{m}

a = \frac{4.8423-(0.445)(9.8)sin(35)}{0.445}a = 10.31m/s^2

Therefore the box is accelerated upward.

3 0
3 years ago
Which one of the following statements concerning emf is true?
Andrej [43]

Answer:

C) Emf is the force exerted on a single charge to move it from one terminal to the other of an emf device.

Explanation:

Electromotive force, abbreviation E or emf, electrical energy per unit supplied from an energy source, such as an electrical generator or a battery. In the engine or battery, electricity is transformed from one source to another as the device works on the electrical charge that is passed within itself.

In physics it is defined as Work done by a cell or battery in moving a unit charge from its one terminal to the other, against the potential.

Hence C is correct

3 0
3 years ago
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