Question

(-1,-4) 9x+3y=8 Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph

Answer 1

$9x+3y=8\ \ \ | subtract\ 9x\\\\ 3y=8-9x\ \ \ | divide\ by\ 3\\\\ y=-3x+\frac{8}{3}\\\\new\ line:\y=ax+b\\\\line\ is\ parallel\ when\ a=-3\\\\ y=-3x+b\ \ \ | substitute\ point \ (-1,-4)\\\\ -4=-3*(-1)+b\\\\ -4=3+b\ \ \ | subtract\ 3\\\\ b=-7\\\\Line\ : \ y=-3x-7$