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3 years ago

What is the equation of the circle with a radius of 5 and center of (2, 3)?

Mathematics

1 answer:

Nady [450]3 years ago

5 0

Answer:

None of the above.

Step-by-step explanation:

The equation should be (x - 2)^2 + (y - 3)^2 = 25

The standard equation of a circle is:

(x - a)^2 + (y - b)^2 = r^2

where (a,b) are the coordinates of the center and r, the radius.

here the center = (2,3) hence a = 2 , b = 3 and r = 5

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Answer:

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4 years ago

Solve the system of equations and choose the correct answer from the list of options.

Igoryamba

Answer:

x = -6/5

y = -8/5

Step-by-step explanation:

2x + y = -4

Y = 3x + 2

Substitute the second equation into the first equation

2x + 3x+2 = -4

Combine like terms

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5x+2-2=-4-2

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3 years ago

Type the correct answer in each box.

Mariulka [41]

Answer:

$(x-5)^2+(y+4)^2=100$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center and any point that lie on the circle is equal to the radius

we have the points

(5,-4) and (-3,2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$r=\sqrt{(2+4)^{2}+(-3-5)^{2}}$

$r=\sqrt{(6)^{2}+(-8)^{2}}$

$r=\sqrt{100}\ units$

$r=10\ units$

step 2

Find the equation of the circle

we know that

The equation of a circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

we have

$(h,k)=(5,-4)\\r=10\ units$

substitute

$(x-5)^2+(y+4)^2=10^2$

$(x-5)^2+(y+4)^2=100$

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3 years ago

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Answer:

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3 years ago

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tensa zangetsu [6.8K]

Answer:

6^8

Step-by-step explanation:

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3 years ago

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