What is the equation of the circle with a radius of 5 and center of (2, 3)?
1 answer:
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Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=
a=-0.04
b=8.3
c=4.3
x=
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=
a=-0.04
b=8.3
c=4.3
x=
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
Answer:
Teresa drive <u>90 miles</u> on Tuesday.
Step-by-step explanation:
Given:
Teresa drove on Monday, Tuesday and Wednesday.
On monday her driving distance was 120 miles.
The ratio of Wednesdays distance is 3/5.
The ratio of Wednesdays distance to Tuesday's distance is 5/4.
Now, to find the miles Teresa drive on Tuesday:
Teresa driving distance on Monday was = 120 miles.
Her driving distance on Wednesday is =
Now, her driving distance on Tuesday is:
Therefore, Teresa drive 90 miles on Tuesday.