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stich3 [128]
3 years ago
9

What is the equation of the circle with a radius of 5 and center of (2, 3)?

Mathematics
1 answer:
Nady [450]3 years ago
5 0

Answer:

None of the above.

Step-by-step explanation:

The equation should be (x - 2)^2 + (y - 3)^2 = 25

The standard equation of a circle is:

(x - a)^2 + (y - b)^2 = r^2

where (a,b) are the coordinates of the center and r, the radius.

here the center = (2,3) hence a = 2 , b = 3 and r = 5

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vesna_86 [32]

Answer:

Step-by-step explanation:

g-(3,3)

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Can someone help please 3x-y=13 A. (6,5) B.(3,-4) C. (6,5) and (3,-4) D. neither
gavmur [86]

Answer:

C. (6, 5) and (3, -4)

Step-by-step explanation:

Given the equation 3x - y = 13, we need to figure out which points satisfy it. In order for an ordered pair to satisfy an equation, when we plug the x-coordinate in for x and the y-coordinate in for y, the equation should hold true.

Let's try with (6, 5):

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3 * 6 - 5 =? 13

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Since this is true, we know that (6, 5) is indeed a solution.

Now let's try with (3, -4):

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3 * (3) - (-4) =? 13

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Again, since this is true, then (3, -4) must be a solution.

Thus, the answer is C.

<em>~ an aesthetics lover</em>

6 0
3 years ago
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Step-by-step explanation

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